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3 years ago

What is the area of the shaded part of the figure?

Mathematics

1 answer:

adoni [48]3 years ago

8 0

Oh all u do is just do the triangle the subtract the square from that

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You need to drive to a game that is 320 miles away. You have 5.5

kaheart [24]

Thing is, you didn't give us the choices!

7 0

3 years ago

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Find the value of X (Gotta choose at least 2) x = 52 x = 2 x = 3 x = 33

Ad libitum [116K]

Answer:

Before this problem gets an answer, can you define "gotta." Does this work mean isosceles?

Step-by-step explanation:

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3 years ago

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Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?

Flura [38]

Answer:

The value to the given expression is 8

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3$

To find the value of the given expression:

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}$

( By using the property ( $(\frac{a}{b})^m=\frac{a^m}{b^m}$ )

$=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}$

( By using the property $(ab)^m=a^mb^m$ )

$=\frac{(10^{12})(5^6)}{(10^9)(5^9)}$

( By using the property $(a^m)^n=a^{mn}$ )

$=(10^{12})(5^6)(10^{-9})(5^{-9})$

( By using the property $\frac{1}{a^m}=a^{-m}$ )

$=(10^{12-9})(5^{6-9})$ (By using the property $a^m.b^n=a^{m+n}$ )

$=(10^3)(5^{-3})$

$=\frac{10^3}{5^3}$ ( By using the property $a^{-m}=\frac{1}{a^m}$ )

$=\frac{1000}{125}$

$=8$

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Therefore the value to the given expression is 8

3 0

3 years ago

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What does AE equal to ?

sasho [114]

Answer:

i think its 70

Step-by-step explanation:

35+35=70

because line ## is same as ## and ##

3 0

3 years ago

It is known that the distance in metres through which a body falls freely varies directly as the square of the time taken. If a

erma4kov [3.2K]

Answer:

125 meters

Step-by-step explanation:

Let distance = d and time is t

Using the variation;

d = k t^2

So let’s us get k

80 = k * 4*2

16k = 80

k = 80/16 = 5

So for 5 seconds, the distance would be;

d = 5 * 5^2

d = 125 meters

4 0

3 years ago