Contrast oxidation and reduction.
2 answers:
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Answer:
174,957.143 grams of potassium and 89,228.478 grams of potassium nitrate will be needed.
Explanation:
Mass of nitrogen = 27 lbs = 12,247 g
1 lbs = 453.592 g
Moles of nitrogen =
According to reaction, 1 mole of nitrogen is produced from 5 moles of potassium and 1 mole of potassium nitrate.
Then 874.786 mol of nitrogen will be obtained from :
of potassium.
Then 874.786 mol of nitrogen will be obtained from :
of potassium nitrate.
Mass of 4,373.928 moles of potassium:
of potassium
Mass of 874.789 moles of potassium nitrate:
of potassium nitrate