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JulijaS [17]
3 years ago
8

CAN SOMEONE PLEASE HELP ME!!!! I CAN'T GET ANY HELP IN THE SCIENCE SECTION!!!!!

Chemistry
2 answers:
stepan [7]3 years ago
8 0
A chemical property would have to be something that changes and produces new substances. That is one of the main aspects of chemical changes/properties.

Heating an object to determine it's melting point is a physical property.

Shining a bright lighr and testing for decomposition however may be classifieds as a chemical properties because in the process of decomposition, organic substances are being broken. In physical properties, substances are not being broken.
lorasvet [3.4K]3 years ago
6 0
Answer: shining a bright light on the object and testing for decomposition

Decomposition is the separation of a molecule into its elements or simpler compounds.

And a chemical property is the ability of a substance to combine or to become one or more substances.

Then, testing the ability of an object for decomposition is testing a chemical property.

 

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___________ polymers can be produced in large quantities at low cost. please. thank you.
MA_775_DIABLO [31]

Answer:

Plastic polymers

Explanation:

Plastic polymers are usually made up of synthetic and semi-synthetic polymers such as polyethylene, polystyrene etc.

Plastic polymers have a unique property called malleability. Malleability is the ability of a substance to be moulded into different sizes and shapes.

When hear is applied plastics gets soft and can be molded into different forms and then it becomes hardened after exposure to air(dried).

The plastic polymers are usually very cheap to produce in large quantities which is why it is very common in industries.

5 0
2 years ago
Which of the following is NOT a characteristic of metals?
lesantik [10]
I can’t see the question :/
5 0
3 years ago
Label each of the descriptions below as theoretical
anzhelika [568]

Answer:

Before performing chemical reactions, it is helpful to know how much product will be produced with given quantities of reactants. This is known as the theoretical yield. This is a strategy to use when calculating the theoretical yield of a chemical reaction. The same strategy can be applied to determine the amount of each reagent needed to produce a desired amount of product.

Explanation:

Reagent Examples

Reagents may be compounds or mixtures. In organic chemistry, most are small organic molecules or inorganic compounds. Examples of reagents include Grignard reagent, Tollens' reagent, Fehling's reagent, Collins reagent, and Fenton's reagent. However, a substance may be used as a reagent without having the word in its name.

3 0
3 years ago
Read 2 more answers
Many types of scientific equipment are used to perform different functions in the science lab. Which of the following combinatio
Phantasy [73]
I guess B is the right one......
4 0
3 years ago
Read 2 more answers
Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

4 0
3 years ago
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