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TiliK225 [7]
3 years ago
11

Determine the mechanical energy of this object. A 2 kg pendelum has a speed of 1 m/s at a height of 1/2 meter

Physics
1 answer:
Readme [11.4K]3 years ago
8 0

Mechanical Energy: 10.81 J given that g = 9.81 \; \text{m}\cdot\text{s}^{-2}.

<h3>Explanation</h3>

The mechanical energy of an object is the sum of its kinetic and potential energy.

Kinetic Energy of this object:

\text{KE} = \dfrac{1}{2} \; m \cdot v^{2} = \dfrac{1}{2} \times 2 \times 1 = 1 \; \text{J}

Gravitational Potential Energy of this object:

g = 9.81 \; \text{m}\cdot\text{s}^{-2}.

\text{PE} = m \cdot g \cdot h = 2 \times 9.81 \times \dfrac{1}{2} = 9.81 \; \text{J}.

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Resultant force is 400-600=-200N.
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According to the chart, one gram of copper and
ad-work [718]

Answer:

C) three

Explanation:

Let gram of gold required be m . Let temperature change in both be Δ t .

heat absorbed = mass x specific heat x change in temperature

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heat absorbed = 1 x .385 x Δt

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4 0
3 years ago
Two ropes are attached to either side of a 100.0 kg wagon as shown below. The rope on the right is pulled at an angle 40.0° rela
NikAS [45]

The acceleration of the wagon is found by applying Newton's Second Law of motion.

1. The responses for question 1 are;

  • x-component of the tension in the rope on the right is approximately <u>91.93 N</u>
  • y-component of the tension in the rope on the right is approximately <u>71.135 N</u>
  • x-component of the tension in the rope on the left is -80.0 N
  • y-component of the tension in the rope on the left is 0

2. The net force in the x-direction is approximately <u>11.93 N</u>

3. The net acceleration of the wagon in the horizontal direction is approximately <u>0.1193 m/s²</u>.

Reasons:

The given parameters are;

Mass of the wagon, m = 100.0 kg

Angle of inclination to the horizontal of the rope to the right, θ = 40.0°

Tension in the rope on the right = 120.0 N

Direction in which the rope on the left is pulled = To the west

Tension in the rope on the left = 80.0 N

1. The <em>x</em> and <em>y</em> component of the tension in the rope on the right are;

x-component = 120.0 N × cos(40.0°) ≈ <u>91.93 N</u>

y-component = 120.0 N × sin(40.0°) ≈ <u>77.135 N</u>

The <em>x</em> and <em>y</em> component of the tension in the rope on the left are;

x-component = 80.0 N × cos(180°) = <u>-80.0 N</u>

y-component = 80.0 N × sin(180°) = <u>0.0 N</u>

2. The net force in the horizontal direction, Fₓ, is found as follows;

Fₓ = The x-component of the rope on the left + The x-component of the rope on the right

Which gives;

Fₓ = 91.93 N - 80.0 N = <u>11.93 N</u>

3. The net acceleration of the block is given as follows;

According to Newton's Second Law of motion, we have;

Force in the horizontal direction, Fₓ = Mass of wagon, m × Acceleration of the wagon in the horizontal direction, aₓ

Fₓ = m × aₓ

Therefore;

\displaystyle a_x = \frac{F_x}{m}  \approx \frac{11.93 \, N}{100.0 \, kg} = \mathbf{0.1193 \ m/s^2}

  • The acceleration of the wagon in the horizontal direction, aₓ ≈ <u>0.1193 m/s²</u>.

Learn more here:

brainly.com/question/20357188

8 0
3 years ago
What is the weight of an object with a mass of 6.0 kg on Earth?
gregori [183]
<h2>since weight is measured in newtons, convert the 6 kg to newtons</h2><h3>the formula to convert is kg x 9.807 = N</h3>
  • 6 x 9.807
  • = 58.842 N

hope that helps :))

3 0
3 years ago
Read 2 more answers
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