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D. For any projectile motion, there is a constant downwards acceleration due to gravity at all instances. This not to be confused with velocity, which changes due to gravity at every moment along the object's path.

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A 97.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 48.0 m/s. If both are initially at rest and if t

OverLord2011 [107]

Answer:

s₁ = 0.022 m

Explanation:

From the law of conservation of momentum:

$m_1u_1 + m_2u_2 = m_1v_1+m_2v_2$

where,

m₁ = mass of hockey player = 97 kg

m₂ = mass of puck = 0.15 kg

u₁ = u₂ = initial velocities of puck and player = 0 m/s

v₁ = velocity of player after collision = ?

v₂ = velocity of puck after hitting = 48 m/s

Therefore,

$(97\ kg)(0\ m/s)+(0.15\ kg)(0\ m/s)=(97\ kg)(v_1)+(0.15\ kg)(48\ m/s)\\\\v_1 = -\frac{(0.15\ kg)(48\ m/s)}{97\ kg} \\v_1 = - 0.074 m/s$

negative sign here shows the opposite direction.

Now, we calculate the time taken by puck to move 14.5 m:

$s_2 =v_2t\\\\t = \frac{s_2}{v_2} = \frac{14.5\ m}{48\ m/s} \\\\t = 0.3\ s$

Now, the distance covered by the player in this time will be:

$s_1 = v_1t\\s_1 = (0.074\ m/s)(0.3\ s)$

4 0

2 years ago

The diagram below shows a subduction zone where oceanic crust is sinking into the mantle underneath continental crust as two

Scrat [10]

Metal ores

Explanation:

in an area where subduction has occurred in times past, metal ores are likely to be found.

Metallic ores find subduction zone regions very favorable to crystallize out of a magma.

Ores have different modes of formation.
Typically, they are found in hydrothermal vents and black smokers of igneous intrusives.
These are igneous terrains where metallic sulfides and other minerals crystallize out of magmatic body.
Metals in magma usually have large sizes and do not partition easily in the melt.

At a subduction zone, partial melting of the subducting plate forces magma into nearby country rock as an intrusive and to the ocean floor where they form black smokers.

Learn more:

Rocks brainly.com/question/2740663

#learnwithBrainly

4 0

3 years ago

An uncharged conductor has a hollow cavity inside of it. Within this cavity there is a charge of +10 µC that does not touch the

aliina [53]

Answer:

Explanation:

we have to make charge inside the conductor zero because we know that electric field inside the conductor should be zero

so, the outer surface of the conductor should contain + 10 uC of charge and the inner surface contains -10 uC

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