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blsea [12.9K]
3 years ago
10

A suitcase (mass m = 18 kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures

0.50 m × 0.15 m. The elevator is moving upward with an acceleration of magnitude 1.6 m/s2. What pressure (in excess of atmospheric pressure) is applied to the floor beneath the suitcase?
Physics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

P=2736 Pa

Explanation:

According to Newton we have that:

∑F=m*a\\

A force is exerted by the elevator to the suitcase, according to 3th Newton's law an equal force but in the opposite direction will appeared on the suitcase, that is:

∑F=m*g+m*a=m*(g+a)

F=205.2N

We know that the pressure is given by:

P=\frac{F}{A}\\P=\frac{205.2N}{(0.50m)*(0.15m)}\\P=2736N/m^2=2736Pa

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In AA&E storage facilities, why must drainage structures be secured if they cross the fence line and meet certain size requi
Likurg_2 [28]

Answer:

As an additional security measure in an AA&E storage facilities, securing drainage structures  must be considered if their cross section is greater than 96 inches  and any dimension is greater  than 6 inches, they must be  barred and welded at the  intersections to prevent any  human from crawling into the  area.

Explanation:

U.S. national security relys on ensuring DoD sensitive or classified assets such as classified material, arms, ammunition, and explosives  (AA&E) and nuclear weapons, in properly safeguard facilites and storage containers, voiding DoD assets loss or  compromise and additional to supplemental intrusion detection systems and guard patrols, security lighting, communications, fences and clear zones, drainage structures, key control, and other security measures required to protect  AA&E.

6 0
3 years ago
Find the average energy E for (a) An n-state system, in which a given state can have energy 0,,2,...,n . (b) A harmonic oscillat
kicyunya [14]

Answer:

a♦1  E_average = n E₀ / 2 , b) E_average= infinity

Explanation:

The energy values ​​form an arithmetic series, whose sum is

          S = n (a₁ + aₙ) / 2 = n (2a₁ + (n-1) r)/ 2

Where n is the number of terms, a₁ is the first term, aₙ the last term and r is the difference between two consecutive numbers in the series

          r = 2E₀ - 0 = 2E₀

Therefore the sum is

       S = n (0 + n E₀) / 2

      S = n² E₀ / 2

     

The average value is

         E_average = S / n

         E_average = n E₀ / 2

b) the case of harmonic oscillation

We have two possibilities.

- if we take a finite number and terms gives the same previous value

- If we take an infinite number of fears the series gives infinity and the average is also infinite

          E_average= infinity

4 0
3 years ago
Two people carry a heavy object by placing it on a board that is 2.2 meters long. One person lifts with a force of 750 N at one
stiks02 [169]

Answer:

This means that the center of mass is locates 0.72m from the 750N force

Explanation:

Since the board is 2.2m long, that will be the length of the board.

Let the center of mass of the body be hinged at the center using a knife edge as shown in the diagram attached.

Let x be the distance from the 750N force to the knife edge and the distance from the 360N force to the knife edge be 2.2-x

Using the principle of moment which states that the sum of clockwise moment is equal to the sum of anti clockwise moment.

Moment = force × perpendicular distance

For ACW moment;

Moment = 750×x = 750x

For the CW moment;

Moment = 360 × (2.2-x)

Moment = 792-360x

Equating ACW moment to the clockwise moment we have;

750x = 792-360x

750x+360x = 792

1110x = 792

x = 792/1110

x = 0.72m

This means that the center of mass is locates 0.72m from the 750N force

3 0
3 years ago
In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes
muminat

Answer:

18.375

Explanation:

Mean = total of measured values / no of elements of sample

Total = .15 + .89 +1.11+1.46 +2.78 + 3.12 + 4.30 + 4.59 + 4.92 + 6.42 + 7.20+8.04+8.21+12.13+31.86+32.53+33.82+36.60+ 72.99

= 273.03

Mean = 273 .03 / 19

= 14.37

( .15 - 14.37 )² +( 0.89 - 14.37 )²+( 1.11- 14.37 )²+( 1.46 - 14.37 )²+( 2.78 - 14.37 )²+( 3.12 - 14.37 )²+( 4.30 - 14.37 )²+( 4.59 - 14.37 )²+( 4.92 - 14.37 )²+( 6.42 - 14.37 )²+( 7.20 - 14.37 )²+( 8.04 - 14.37 )²+( 8.21 - 14.37 )²+( 12.13 - 14.37 )²+( 31.86 - 14.37 )²+( 32.53 - 14.37 )²+( 33.82 - 14.37 )²+( 36.60 - 14.37 )²+( 72.99 - 14.37 )²

= 202.20 +181.71+ 175.82 + 166.66+ 134.32 + 126.56 + 101.40 +95.64 + 89.30 +63.20 +51.40 +40.06 +37.94+5.01 +305.90 +329.78 +378.30 +494.17 +3436.30

=6415.67

Standard deviation =

\sqrt{\frac{6415.67}{19} }

= 18.375

5 0
3 years ago
How do you graph distance and time for an object that moves at a constant speed?
LekaFEV [45]

Answer:

It would be a straight line

Explanation:

On a distance-time graph, an object that moves at constant speed would be represented by a straight line.

In fact, in a distance-time graph, the slope of the line corresponds to the speed of the object. We can demonstrate that. In fact:

- The speed of the object is equal to the ratio between the distance covered (\Delta s) and the time taken (\Delta t):

v=\frac{\Delta s}{\Delta t}

On a distance-time graph, the distance is on the y-axis while the time is on the x-axis. The slope of the line is defined as:

m=\frac{\Delta y}{\Delta x}

But the variation on the y-axis (\Delta y) is equal to the distance covered (\Delta s), while the variation on the x-axis (\Delta x) corresponds to the time taken (\Delta t), so the slope can also be rewritten as

m=\frac{\Delta s}{\Delta t}

which is equal to the speed of the object. Therefore, an object moving at constant speed would be represented by a line with constant slope, which means a straight line.

6 0
3 years ago
Read 2 more answers
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