Answer:
As an additional security measure in an AA&E storage facilities, securing drainage structures must be considered if their cross section is greater than 96 inches and any dimension is greater than 6 inches, they must be barred and welded at the intersections to prevent any human from crawling into the area.
Explanation:
U.S. national security relys on ensuring DoD sensitive or classified assets such as classified material, arms, ammunition, and explosives (AA&E) and nuclear weapons, in properly safeguard facilites and storage containers, voiding DoD assets loss or compromise and additional to supplemental intrusion detection systems and guard
patrols, security lighting, communications, fences and clear zones, drainage structures, key control, and other security measures required to protect AA&E.
Answer:
a♦1 E_average = n E₀ / 2
, b) E_average= infinity
Explanation:
The energy values form an arithmetic series, whose sum is
S = n (a₁ + aₙ) / 2 = n (2a₁ + (n-1) r)/ 2
Where n is the number of terms, a₁ is the first term, aₙ the last term and r is the difference between two consecutive numbers in the series
r = 2E₀ - 0 = 2E₀
Therefore the sum is
S = n (0 + n E₀) / 2
S = n² E₀ / 2
The average value is
E_average = S / n
E_average = n E₀ / 2
b) the case of harmonic oscillation
We have two possibilities.
- if we take a finite number and terms gives the same previous value
- If we take an infinite number of fears the series gives infinity and the average is also infinite
E_average= infinity
Answer:
This means that the center of mass is locates 0.72m from the 750N force
Explanation:
Since the board is 2.2m long, that will be the length of the board.
Let the center of mass of the body be hinged at the center using a knife edge as shown in the diagram attached.
Let x be the distance from the 750N force to the knife edge and the distance from the 360N force to the knife edge be 2.2-x
Using the principle of moment which states that the sum of clockwise moment is equal to the sum of anti clockwise moment.
Moment = force × perpendicular distance
For ACW moment;
Moment = 750×x = 750x
For the CW moment;
Moment = 360 × (2.2-x)
Moment = 792-360x
Equating ACW moment to the clockwise moment we have;
750x = 792-360x
750x+360x = 792
1110x = 792
x = 792/1110
x = 0.72m
This means that the center of mass is locates 0.72m from the 750N force
Answer:
18.375
Explanation:
Mean = total of measured values / no of elements of sample
Total = .15 + .89 +1.11+1.46 +2.78 + 3.12 + 4.30 + 4.59 + 4.92 + 6.42 + 7.20+8.04+8.21+12.13+31.86+32.53+33.82+36.60+ 72.99
= 273.03
Mean = 273 .03 / 19
= 14.37
( .15 - 14.37 )² +( 0.89 - 14.37 )²+( 1.11- 14.37 )²+( 1.46 - 14.37 )²+( 2.78 - 14.37 )²+( 3.12 - 14.37 )²+( 4.30 - 14.37 )²+( 4.59 - 14.37 )²+( 4.92 - 14.37 )²+( 6.42 - 14.37 )²+( 7.20 - 14.37 )²+( 8.04 - 14.37 )²+( 8.21 - 14.37 )²+( 12.13 - 14.37 )²+( 31.86 - 14.37 )²+( 32.53 - 14.37 )²+( 33.82 - 14.37 )²+( 36.60 - 14.37 )²+( 72.99 - 14.37 )²
= 202.20 +181.71+ 175.82 + 166.66+ 134.32 + 126.56 + 101.40 +95.64 + 89.30 +63.20 +51.40 +40.06 +37.94+5.01 +305.90 +329.78 +378.30 +494.17 +3436.30
=6415.67
Standard deviation =

= 18.375
Answer:
It would be a straight line
Explanation:
On a distance-time graph, an object that moves at constant speed would be represented by a straight line.
In fact, in a distance-time graph, the slope of the line corresponds to the speed of the object. We can demonstrate that. In fact:
- The speed of the object is equal to the ratio between the distance covered
and the time taken (
):

On a distance-time graph, the distance is on the y-axis while the time is on the x-axis. The slope of the line is defined as:

But the variation on the y-axis (
) is equal to the distance covered (
), while the variation on the x-axis
corresponds to the time taken (
), so the slope can also be rewritten as

which is equal to the speed of the object. Therefore, an object moving at constant speed would be represented by a line with constant slope, which means a straight line.