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3 years ago

6. A car drives 750 miles in 10 hours. Calculate the speed of the truck .

Physics

1 answer:

Dmitriy789 [7]3 years ago

3 0

Answer:

75 miles an hour

I hope this is correct and helps

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Nat2105 [25]

Answer:

wat

Explanation:

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2 years ago

A race car decelerating by 3 m /s to 10 m / s has an acceleration of 25

Scilla [17]

Answer:

then it will stop

Explanation:

7 0

3 years ago

A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnet

Amanda [17]

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance $R= 10\Omega$

We need to calculate the speed of the wire

Using formula of emf

$\epsilon=Bvl$

Using formula of current

$I=\dfrac{\epsilon}{R}$

Put the value of $\epsilon$ into the formula of current

$I=\dfrac{Bvl}{R}$

$v=\dfrac{IR}{Bl}$

$v=\dfrac{10\times10^{-3}\times10}{0.1\times20\times10^{-2}}$

$v= 5\ m/s$

Hence, The speed of the wire is 5 m/s.

6 0

3 years ago

Describe how we know the plates once formed a supercontinent and how we know this.

Lady_Fox [76]

Answer:

<h3>How did scientists “discover” Pangea and other supercontinents of the past?</h3>

Nowadays, they can study the geologic record and use radioactive dating, seismic surveys, and other technologies to construct maps of how the world looked at various points in Earth's history.

3 0

2 years ago

A 2.00-m long uniform beam has a mass of 4.00 kg. The beam rests on a fulcrum that is 1.20 m from its left end. In order for the

Shalnov [3]

Answer:

x ’= 1,735 m, measured from the far left

Explanation:

For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.

Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive

They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,

the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar

x_{cm} = 1.2 -1

x_ {cm} = 0.2 m

Σ τ = 0

w₁ 1.2 + mg 0.2 - W₂ x = 0

x = $\frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}$

x = $\frac{m_1 \ 1.2 \ + m \ 0.2 }{M_2}$

let's calculate

x = $\frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}$ 2.9 1.2 + 4 0.2 / 8

x = 0.535 m

measured from the pivot point

measured from the far left is

x’= 1,2 + x

x'= 1.2 + 0.535

x ’= 1,735 m

8 0

3 years ago