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pychu [463]
4 years ago
11

The energy required to remove an electron from a gaseous atom is called

Physics
1 answer:
IRISSAK [1]4 years ago
6 0

Answer: The energy required to remove an electron from a gaseous atom is called ionization energy.

Explanation:

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period but decreases along a group.

Smaller is the size of an atom more will be the force of attraction between its protons and electrons. Hence, more amount of energy is required to remove an electron.

Thus, we can conclude that the energy required to remove an electron from a gaseous atom is called ionization energy.

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How did the discovery of eris force astronomers to reconsider the definition of planet?
kogti [31]

Answer:

Explanation:

They had demoted Pluto on the basis of the discovery of Eris. They also discovered that Eris had a moon. It was thought to be much bigger than Pluto. That turned out not to be true. So having accepted Eris as a planet, they had to consider carefully what to do about Pluto. It has a gravitational constant of 0.82 m/s^2 which is 8.4% of that of our gravitational pull. and slightly more than Pluto.

Later data showed that these two  objects in space were more like twins and that's what shook up the definition of a planet. You can't demote one and not the other.

5 0
3 years ago
Once the genes are copied, where do they go?
Anna [14]

By copying their genomes, they retain the tool kit and at the same time generate a garage full of spare parts. Gene duplication can provide the raw material for expression changes to occur, and polyploidy itself can trigger epigenetic changes

5 0
3 years ago
A positive or negative outcome of a decision or action can be called a
Mandarinka [93]
The answer to this would be :
<span>consequence
</span>hope that this helps you! 
Source: I had done a research about this. =)
7 0
3 years ago
The length of a certain wire is doubled and at the same time its radius is also doubled. What is the new resistance of this wire
Leto [7]

Answer:

R' = R/2

Therefore, the new resistance of the wire is twice the value of the initial resistance.

Explanation:

Consider a wire with:

Resistance = R

Length = L

Area = A = πr²

where, r = radius

ρ = resistivity

Then:

R = ρL/A

R = ρL/πr²   --------------- equation 1

Now, the new wire has:

Resistance = R'

Resistivity = ρ

Length = L' = 2 L

Radius = r' = 2r

Area = πr'² = π(2r)² = 4πr²

Therefore,

R' = ρL'/πr'²

R' = ρ(2 L)/4πr²

R' = (1/2)(ρL/πr²)

using equation 1:

<u>R' = R/2</u>

<u>Therefore, the new resistance of the wire is twice the value of the initial resistance.</u>

4 0
3 years ago
A He–Ne laser illuminates a narrow, single slit that is 1850 nm wide. The first dark fringe is found at an angle of 20.0∘ from t
egoroff_w [7]

Answer:

Wavelength of light will be 632.73 nm

Explanation:

We have given width of the single slit d=1850nm-1850\times 10^{-9}m

Angle is given as \Theta =20^{\circ}

We have to find the wavelength of light for first dark fringe

We know that for dark fringe it is given that

dsin\Theta =n\lambda

For first fringe n = 1

So 1850\times 10^{-9}\times sin20^{\circ} =1\times \lambda

\lambda =632.73nm

3 0
3 years ago
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