Answer:
The molar concentration of this solution is 0.0463 mol/L
Explanation:
Step 1 : Data given
Mass of a nonelectrolyte solute = 2.69 grams
Volume of water = 345 mL = 0.345 L
Temperature = 26.0°CC = 273 + 26 = 299 K
The osmotic pressure = 863 torr
⇒ 863torr /760 = 1.13553 atm
Step 2: Calculate the molar concentration of this solution
Π = i*M*R*T
⇒with Π = the osmotic pressure = 1.13553 atm
⇒with i = the van't Hoff factor of the nonelectrolyte solute = 1
⇒with M = the molar concentration = TO BE DETERMINED
⇒with R = the gas constant = 0.08206 L*atm/mol*K
⇒with T = the temperature = 299 K
1.13553 atm = 1 * M * 0.08206 L*atm/mol*K * 299 K
M = 1.13553 / (0.08206*299)
M = 0.0463 mol/L
The molar concentration of this solution is 0.0463 mol/L
Answer:
because a fruit holds the seeds it needs to reproduce and continue living.
For Iron:
For Oxygen:
These are the two chemical symbols for the two elements found in Iron Oxide.
Answer:
The ideal gas law is expressed mathematically by the ideal gas equation as follows;
P·V = n·R·T
Where;
P = The gas pressure
V = The volume of the gas
n = The number of moles of the gas present
R = The universal gas constant
T = The temperature of the gas
A situation where the ideal gas law is exhibited is in the atmosphere just before rainfall
The atmospheric temperature of the area expecting rainfall drops, (when there is appreciable blockage of the Sun's rays by cloud covering) followed by increased wind towards the area, which indicates that the area was in a state of a low pressure, 'P', and or volume, 'V', or a combination of both low pressure and volume P·V
When the entry flow of air into the area is observed to have reduced, the temperature of the air in the area is simultaneously sensed to have risen slightly, therefore, the combination of P·V is seen to be proportional to the temperature, 'T', and the number of moles of air particles, 'n' in the area
Explanation:
