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3 years ago

The change in position is known as

Physics

1 answer:

Goryan [66]3 years ago

4 0

Answer:

distance or displacement

Explanation:

the answer can be displacement or displacement. if the required measure is between two points, we can call it as distance. but if we are to find the distance moved, we call it displacement. though it sounds pretty similar, they are very different. displacement is the shortest distance of movement of a body to its final point (or to the asked point) and distance is the total distance travelled by the body. and while distance is a scalar quantity, that this value shows the magnitude, displacement is a vector quantity, that this value should show both magnitude and direction.

for example if an object travels from point A to point B that is a 10 meters away and back, the distance will be 10+10 which is 20 meters. but the displacement is 0!

since not much information is given, the answer can be both distance or displacement

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A 600 N force acts on an object with a mass of 50 kg. What is the resulting acceleration of the object?

DochEvi [55]

Answer:

<h3>The answer is 12 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{600}{50} = \frac{60}{5} \\$

We have the final answer as

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2 years ago

Calculate the mechanical advantage of a hammer, if the input force is 125 N

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Answer:

Explanation:

Mechanical advantage = force out / force in

MA = 2000 N / 125 N

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3 years ago

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3 years ago

A 5.50 kg sled is initially at rest on a frictionless horizontal road. The sled is pulled a distance of 3.20 m by a force of 25.

kiruha [24]

(a) 69.3 J

The work done by the applied force is given by:

$W=Fd cos \theta$

where:

F = 25.0 N is the magnitude of the applied force

d = 3.20 m is the displacement of the sled

$\theta=30^{\circ}$ is the angle between the direction of the force and the displacement of the sled

Substituting numbers into the formula, we find

$W=(25.0 N)(3.20 m)(cos 30^{\circ})=69.3 J$

(b) 0

The problem says that the surface is frictionless: this means that no friction is acting on the sled, therefore the energy dissipated by friction must be zero.

(c) 69.3 J

According to the work-energy theorem, the work done by the applied force is equal to the change in kinetic energy of the sled:

$\Delta K = W$

where

$\Delta K$ is the change in kinetic energy

W is the work done

Since we already calculated W in part (a):

W = 69.3 J

We therefore know that the change in kinetic energy of the sled is equal to this value:

$\Delta K=69.3 J$

(d) 4.9 m/s

The change in kinetic energy of the sled can be rewritten as:

$\Delta K=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2$ (1)

where

Kf is the final kinetic energy

Ki is the initial kinetic energy

m = 5.50 kg is the mass of the sled

u = 0 is the initial speed of the sled

v = ? is the final speed of the sled

We can calculate the variation of kinetic energy of the sled, $\Delta K$ , after it has travelled for d=3 m. Using the work-energy theorem again, we find

$\Delta K= W = Fd cos \theta =(25.0 N)(3.0 m)(cos 30^{\circ})=65.0 J$

And substituting into (1) and re-arrangin the equation, we find

$v=\sqrt{\frac{2 \Delta K}{m}}=\sqrt{\frac{2(65.0 J)}{5.50 kg}}=4.9 m/s$

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3 years ago

The 2779-m Brooklyn-Battery Tunnel, connecting Brooklyn and Manhattan, is one of the world's longest underwater vehicular tunnel

Marina CMI [18]

For a cylinder that has both ends open resonant frequency is given by the following formula:
$f= \frac{nv}{2L}$
Where n is the resonance node, v is the speed of sound in air and L is the length of a cylinder.
The fundamental frequency is simply the lowest resonant frequency.
We find it by plugging in n=1:
$f_0= \frac{v}{2L}=\frac{343}{2\cdot 2779}=0.062 Hz$
To find what harmonic has to be excited so that it resonates at f>20Hz we simply plug in f=20 Hz and find our n:
$20= \frac{n343}{2\cdot 2779} =n\cdot f_0$
We can see that any resonant frequency is simply a multiple of a base frequency.
Let us find which harmonic resonates with the frequency 20 Hz:
$20=n\cdot f_0\\ n=\frac{20}{0.062}=322.58$
Since n has to be an integer, final answer would be 323.

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3 years ago