Answer:
The value of acceleration that accomplishes this is 8.61 ft/s² .
Explanation:
Given;
maximum distance to be traveled by the car when the brake is applied, d = 450 ft
initial velocity of the car, u = 60 mph = (1.467 x 60) = 88.02 ft/s
final velocity of the car when it stops, v = 0
Apply the following kinematic equation to solve for the deceleration of the car.
v² = u² + 2as
0 = 88.02² + (2 x 450)a
-900a = 7747.5204
a = -7747.5204 / 900
a = -8.61 ft/s²
|a| = 8.61 ft/s²
Therefore, the value of acceleration that accomplishes this is 8.61 ft/s² .
<h2>Answer:</h2>
The refractive index is 1.66
<h2>Explanation:</h2>
The speed of light in a transparent medium is 0.6 times that of its speed in vacuum
.
Refractive index of medium = speed of light in vacuum / speed of light in medium
So
RI = 1/0.6 = 5/3 or 1.66
Answer:
1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday
Explanation:
1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday
Answer:
The description including its issue is summarized throughout the clarification portion below.
Explanation:
- Speed would be a measurement of size. Which has only significance and therefore no path or guidance. Student says acceleration of -10m/s, therefore this assumption is incorrect because this same negative correlation indicates the path.
- In reality, this same participant defined the speed (which seems to have two very different motion of an object).
