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Brut [27]
3 years ago
11

According to the first law of thermodynamics, the amount of work done by a heat engine equals the amount of

Chemistry
2 answers:
sasho [114]3 years ago
5 0

Answer:

The correct answer is option C.

Explanation:

The first law: thermodynamics:

\Delta U=Q-w

Q = heat added to the system

w = work done by the system

\Delta U = Internal energy

w=Q-\Delta U

The work done by the system is equal to the difference of energy added to the system from the internal energy.This internal energy of the system is the energy which is left unused and given out to the surrounding by the heat engine in the form of thermal energy.

Naddika [18.5K]3 years ago
4 0

B is the correct answer to this problem


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The two electrons that share an orbital repel each other.

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Explanation:

Because electrons have the same negative charge, they repel each other especially when they occupy the same orbital shell in an atom. To reduce this repulsion, each of the electrons in the orbital shell (remember electrons occupy orbital shells of atoms in 2s) assumes an opposite quantum (M<em>s</em>) spin; one with  – ½ while the other + ½ .

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If you assume this reaction is driven to completion because of the large excess of one ion, what is the concentration of [Fe(SCN
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Answer : The concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

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When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is SCN^- and Fe^{3+} is excess reagent.

First we have to calculate the moles of KSCN.

\text{Moles of }KSCN=\text{Concentration of }KSCN\times \text{Volume of solution}

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Now we have to calculate the concentration of [Fe(SCN)]^{2+}

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}

Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M

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