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3 years ago

According to the first law of thermodynamics, the amount of work done by a heat engine equals the amount of

Chemistry

2 answers:

sasho [114]3 years ago

5 0

Answer:

The correct answer is option C.

Explanation:

The first law: thermodynamics:

$\Delta U=Q-w$

Q = heat added to the system

w = work done by the system

$\Delta U$ = Internal energy

$w=Q-\Delta U$

The work done by the system is equal to the difference of energy added to the system from the internal energy.This internal energy of the system is the energy which is left unused and given out to the surrounding by the heat engine in the form of thermal energy.

Naddika [18.5K]3 years ago

4 0

B is the correct answer to this problem

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FinnZ [79.3K]

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8 0

3 years ago

Newton's second law of motion uses the formula which states that a force will cause a mass to accelerate. (f = m •

Makovka662 [10]

Newton's second law of motion can be formally stated as follows:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

This verbal statement can be expressed in equation form as follows:

a = Fnet / m

7 0

3 years ago

Read 2 more answers

46.6 grams of mercury II sulfate (HgSO4) reacts with an excess of sodium Chloride (NaCl). How many grams of mercury II chloride

slega [8]

Answer:

$m_{HgCl_2}=42.7gHgCl_2$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4$

In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:

$m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2$

Best regards.

3 0

3 years ago

Nitrogen and water react to form nitrogen monoxide and hydrogen, like this: N2(g) + 2H2O(g) → 2NO(g) +2H2(g) Also, a chemist fin

Thepotemich [5.8K]

Answer:

Kc for this reaction is 0.43

Explanation:

This is the equilibrium:

N₂(g) + 2H₂O(g) → 2NO(g) +2H₂(g)

And we have all the concentration at equilibrium:

N₂: 0.25M

H₂ : 1.3M

NO: 0.33M

H₂: 1.2M

They are ok, because they are in MOLARITY. (mol/L)

Let's make the expression for Kc

Kc = ( [NO]² . [H₂]² ) / ([N₂] . [H₂O]²)

Kc = (0.33² . 1.2²) / (0.25 . 1.2²)

Kc = 0.4356

In two significant digits. 0.43

8 0

3 years ago

C55H72MgN4O5. How many atoms are in this molecule?

Bas_tet [7]

There are 137 atoms in this molecule. C55 + H72 = 127. 127 + Mg (one atom of magnesium = 128. 128 + N4 = 132. 132 + O5 = 137.

5 0

3 years ago