According to the first law of thermodynamics, the amount of work done by a heat engine equals the amount of
2 answers:
Answer:
The correct answer is option C.
Explanation:
The first law: thermodynamics:
Q = heat added to the system
w = work done by the system
= Internal energy
The work done by the system is equal to the difference of energy added to the system from the internal energy.This internal energy of the system is the energy which is left unused and given out to the surrounding by the heat engine in the form of thermal energy.
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Answer:
ΔS = +541.3Jmol⁻¹K⁻¹
Explanation:
Given parameters:
Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹
Standard Entropy of C = 5.7Jmol⁻¹K⁻¹
Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹
Standard Entropy of CO = 198Jmol⁻¹K⁻¹
To find the entropy change of the reaction, we first write a balanced reaction equation:
Fe₂O₃ + 3C → 2Fe + 3CO
To calculate the entropy change of the reaction we simply use the equation below:
ΔS = ∑S - ∑S
Therefore:
ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1
ΔS = +541.3Jmol⁻¹K⁻¹