Ask question

Ask question

All categories

4 years ago

10

For question numbers 1 and 2, two statements are given - one labelled

1 answer:

Svetllana [295]4 years ago

5 0

Answer:

(iv) (A) is false, but (R) is true.

Explanation:

It is not true that carbon has a strong tendency to either lose or gain electrons to attain noble gas configuration. Carbon is a member of group 14, it is the first member of the group and carbon is purely a non metal. Only metals metals can loose electrons to attain the noble gas configuration. Moreover, carbon does not participate in ionic bonding so it does not gain electrons to attain the noble gas configuration.

However, carbon participates in covalent bonding where it is covalently bonded to four other chemical species using its four outermost electrons. Carbon forms covalent bonds in which four electrons are shared with other chemical species.

You might be interested in

What are the transition metals

Valentin [98]

Theyre the big bunched up group in the middle of the periodic table

8 0

3 years ago

Read 2 more answers

a single atom of an element had 21 neutrons, and 20 electrons, and 20 protons which element is it ? K. Zr. Ca. Sc

Daniel [21]

You element is calcium.

3 0

3 years ago

Read 2 more answers

What type of energy results from the

jeka94

Answer:

C fghhtrsfeagutyrwraqedf

3 0

3 years ago

Glycine, C2H5O2N, is important for biological energy. The combustion reaction of glycine is described by the following thermoche

vredina [299]

Answer:

-537.25 kJ/mol is the standard enthalpy of formation of solid glycine.

Explanation:

$4C_2H_5O_2N(s) + 9O_2(g)\rightarrow 8CO_2(g) + 10H_2O(l) + 2N_2(g) ,\Delta H^{rxn} =-3896 kJ/mol$

Standard enthalpy of formation of oxygen gas= $\Delta H_{f,O_2}=0$

Standard enthalpy of formation of carbon dioxide= $\Delta H_{f,CO_2}=-393.5 kJ/mol$

Standard enthalpy of formation of water = $\Delta H_{f,H_2O}=-285.8 kJ/mol$

Standard enthalpy of formation of nitrogen gas= $\Delta H_{f,N_2}=0$

Standard enthalpy of formation of glycine = $\Delta H_{f,gly}=?$

Enthalpy of the reaction = $H_{rxn}=-3896 kJ/mol$

$H_{rxn} =$

= $8\times \Delta H_{f,CO_2} +10\times \Delta H_{f,H_2O}+2\times \Delta H_{f,N_2} - (4\times \Delta H_{f,gly}+9\times \Delta H_{f,O_2})$

$-3896 kJ/mol=8\times (-393.5 kJ/mol)+ 10\times (-285.8 kJ/mol)+0 - (4\times \Delta H_{f,gly} +0)$

On rearranging :

$4\times \Delta H_{f,gly}=8\times (-393.5 kJ/mol)+ 10\times (-285.8 kJ/mol)+ 3896 kJ/mol$

$\Delta H_{f,gly}=\frac{-2149 kJ/mol}{4}=-537.25 kJ/mol$

-537.25 kJ/mol is the standard enthalpy of formation of solid glycine.

6 0

3 years ago

Pure iron has a mass of 5.00 grams what’s the calculation of its volume

mart [117]

Answer:

0.635 cm³

Explanation:

You divide the mass by the density of iron (7.87 g/cm³)

<em>D = m</em>/<em>V</em> Multiply both sides by V.

<em>DV = m</em> Divide both sides by D.

<em>V</em> = <em>m</em>/<em>D</em> Insert the values.

<em>V </em>= 5.00/7.87 Do the division.

<em>V</em> = 0.635 cm³

5 0

3 years ago