Answer:
ok soo
Explanation:
first of all...that's not maths that looks like some type of alien language
Molality is the moles of solute per kg of solvent.
Moles of NH₄Cl = 2.4 / (14 + 4 x 1 + 35.5)
= 0.0448 mole
Molality = 0.0448 / (19.4 / 1000)
= 2.31 m
Answer:
56 g. Option 3.
Explanation:
The reaction is: CaCN₂ + 3H₂O → CaCO₃ + 2 NH₃
1 mol of calcium cianide reacts with 3 moles of water in order to produce 1 mol of calcium carbonate and 2 moles of ammonia
We have the mass of each reactant, so let's convert the mass to moles:
45 g. 1mol / 80.08 g = 0.562 moles of cianide
45 g. 1mol / 18 g = 2.5 moles of water
The cianide is the limiting reactant:
3 moles of water need 1 mol of cianide to react
Then, 2.5 moles of water will need (2.5 . 1)/ 3 = 0.833 moles
As we have 0.562 moles of CN⁻ we don't have enough
We can work now, on the reaction:
Ratio is 1:1. Therefore 0.562 moles of cianide will produce 0.562 moles of carbonate
Let's convert the mass to moles to find the answer:
0.562 mol . 100.08 g / 1 mol = 56.2 g
Answer:
Mass = 2.89 g
Explanation:
Given data:
Mass of NH₄Cl = 8.939 g
Mass of Ca(OH)₂ = 7.48 g
Mass of ammonia produced = ?
Solution:
2NH₄Cl + Ca(OH)₂ → CaCl₂ + 2NH₃ + 2H₂O
Number of moles of NH₄Cl:
Number of moles = mass/molar mass
Number of moles = 8.939 g / 53.5 g/mol
Number of moles = 0.17 mol
Number of moles of Ca(OH)₂ :
Number of moles = mass/molar mass
Number of moles = 7.48 g / 74.1 g/mol
Number of moles = 0.10 mol
Now we will compare the moles of ammonia with both reactant.
NH₄Cl : NH₃
2 : 2
0.17 : 0.17
Ca(OH)₂ : NH₃
1 : 2
0.10 : 2/1×0.10 = 0.2 mol
Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.17 mol × 17 g/mol
Mass = 2.89 g