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Scrat [10]
2 years ago
9

Which statement describes the formation of a nebula? (35 points)

Chemistry
1 answer:
expeople1 [14]2 years ago
8 0

Gases from a dead star gather and contract statement describes the formation of a nebula.

<u>Option: D</u>

<u>Explanation:</u>

  • A nebula is a massive cloud of spatially dust and gas. Many nebulae derive from the gas and dust pushed out by a dying star's eruption, like a supernova. Other nebulae are environments where the formation of new stars begins.
  • Five forms of cloudy or nebulous celestial bodies are planetary nebulae, emission nebulae, transparent nebulae, supernova remnants and dark nebulae.
  • The He and H are predominantly responsible for dust and gases, which are widespread but gravity can begin to pull around each other clusters of dust and gas gradually.
  • As these clusters grow bigger and bigger, their gravity becomes better and better. The clump of dusts and gases finally becomes so heavy that it drops from its own gravity.
You might be interested in
Help please and thank you
Ipatiy [6.2K]

Answer:

Opcion D

Explanation:

Una desintegración beta es de a forma:

0

   \beta

-1

You can find this in opcion D

I hope I will help you : )

3 0
3 years ago
A glass sphere is filled to full volume with a gas. The pressure of the gas inside the sphere is 30.0 atm, and the temperature i
harkovskaia [24]

Answer:

28atm

Explanation:

Using Gay lussac's law equation as follows:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

T1 = initial temperature (K)

P2 = final pressure (atm)

T2 = final temperature (K)

Based on the information provided in this question;

P1 = 30.0 atm, T1 = 30.0°C, P2 = ?, T2 = 10.0°C

NOTE: Absolute temperature i.e. Kelvin is required for this law

T1 = 30°C + 273K = 303K

T2 = 10°C + 273K = 283K

Using P1/T1 = P2/T2

30/303 = P2/283

Cross multiply

P2 × 303 = 30 × 283

303P2 = 8490

P2 = 8490/303

P2 = 28.02

New pressure of the gas = 28atm

4 0
2 years ago
Naturally occurring copper exists in two isotopic forms: 63Cu and 65Cu. The atomic mass of copper is 63.55 amu. What is the appr
Mariulka [41]
To calculate the average atomic weight, each exact atomic weight is multiplied by its percent abundance, then, add the results together.  If the natural abundance of 63Cu is assigned x, the natural abundance of 65Cu is 1-x (the two abundance always add up to 1). So the solution is: (63)(x)+(65)(1-x) = 63.55, 63x+65-65x=63.55, x=0.725=72.5%. The natural abundance of 63Cu is 72.5%, that of 65Cu is 1-72.5%=27.5%.
3 0
3 years ago
Helppppppppppppppppppppp
grandymaker [24]

Answer:

Formation of sedimentary rocks

Explanation:

I believe this is correct, May I get a brainliest???

3 0
2 years ago
1. Calculate the heat change associated with cooling a 350.0 g aluminum bar from
Amanda [17]

Answer:

14175 j heat released.

Explanation:

Given data:

Mass of aluminium = 350.0 g

Initial temperature = 70.0°C

Final temperature = 25.0°C

Specific heat capacity of Aluminium = 0.9 j/g.°C

Heat changed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Heat change:

ΔT = Final temperature - initial temperature

ΔT = 25.0°C - 70°C

ΔT = -45°C

Q = m.c. ΔT

Q = 350 g × 0.9 j/g.°C  × -45°C

Q = -14175 j

7 0
2 years ago
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