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Scrat [10]
2 years ago
9

Which statement describes the formation of a nebula? (35 points)

Chemistry
1 answer:
expeople1 [14]2 years ago
8 0

Gases from a dead star gather and contract statement describes the formation of a nebula.

<u>Option: D</u>

<u>Explanation:</u>

  • A nebula is a massive cloud of spatially dust and gas. Many nebulae derive from the gas and dust pushed out by a dying star's eruption, like a supernova. Other nebulae are environments where the formation of new stars begins.
  • Five forms of cloudy or nebulous celestial bodies are planetary nebulae, emission nebulae, transparent nebulae, supernova remnants and dark nebulae.
  • The He and H are predominantly responsible for dust and gases, which are widespread but gravity can begin to pull around each other clusters of dust and gas gradually.
  • As these clusters grow bigger and bigger, their gravity becomes better and better. The clump of dusts and gases finally becomes so heavy that it drops from its own gravity.
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Which element, represented by X, reacts with oxygen to produce the compound X2O?
natali 33 [55]

Answer:

lithium

Explanation:

this is because lithium has a valency of 1 and oxygen has a valency of 2 thereby exchanging valency to create Li²0

7 0
3 years ago
PLEASE HELP &lt;3
frutty [35]
In order for carbon to be stable and have 8 electrons, it must make 4 total covalent bonds.

In prefer for oxygen to be stable and have 8 electrons, it must make 2 covalent bonds.

So, we can deduce that CO2 looks like this:

O=C=O

This molecule has two double bonds.

Pssst...Can I get a brainliest?
8 0
3 years ago
Calculate the energy E of a sample of 3.50 mol of ideal oxygen gas (O2) molecules at a temperature of 310 K. Assume that the mol
love history [14]

Answer:

13.53 kJ

Explanation:

The energy of a gas can be calculated by the equation:

E = (3/2)*n*R*T

Where n is the number of moles, R is the gas constant (8.314 J/mol.K), and T is the temperature.

E = (3/2)*3.5*8.314*310

E = 13,531.035 J

E = 13.53 kJ

7 0
3 years ago
Write a balanced half-reaction describing the reduction of aqueous vanadium(V) cations to aqueous vanadium(I) cations.
11Alexandr11 [23.1K]

Explanation:

Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.

Reduction takes place at the cathode.

In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.

The half reaction is :

V^{5+}(aq)+4e^- \rightarrow V^{1+}(aq)


5 0
3 years ago
Read 2 more answers
How many grams of sodium Phosphate is needed to prepare 5.0 L of a 2.6M solution ?
Diano4ka-milaya [45]

Molarity is the ratio of the moles and the volume. The mass of 2.6 M sodium phosphate solution is 2131.22 gms.

<h3>What is mass?</h3>

Mass is the product of the moles and the molar mass of the substance. It is given as,

Mass = Moles × Molar mass

The moles from molar concentration is used to calculate mass as:

Mass = Molarity × volume × molar mass

= 2.6 × 5.0 × 163.94

= 2131.22 gms

Therefore, 2131.22 gms is the mass of sodium phosphate.

Learn more about mass here:

brainly.com/question/9829994

#SPJ1

6 0
2 years ago
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