2C₃H₇OH + 9O₂ = 6CO₂ + 8H₂O
a₀=2
a₁=9
a₂=6
a₃=8
Answer: G Atom 1 and Atom 4.. hope this helps and good luck!
From the rate law, the information that is given by the rate constant is: C. It tells how much the reaction rate is affected by activation energy.
<h3>
What is the rate law?</h3>
Rate law is also referred to as rate equation and it can be defined as a chemical equation that is typically used to relate the initial (forward) chemical reaction rate with respect to the concentrations or pressures of the chemical reactants and constant parameters.
Mathematically, the rate law is given by this formula:
![R = k[A]^x[B]^y](https://tex.z-dn.net/?f=R%20%3D%20k%5BA%5D%5Ex%5BB%5D%5Ey)
<u>Where:</u>
- A is the concentration of reactant A.
- B is the concentration of reactant B.
In Chemistry, the rate constant is typically used to tell the reaction rate or rate of a chemical reaction that is affected by activation energy.
Read more on rate constant here: brainly.com/question/24749252
Answer:
67.5% ≅ 67.6%
Explanation:
Given data:
Mass of water = 17.0 g
Mass of oxygen produced (actual yield)= 10.2 g
Percent yield of oxygen = ?
Solution:
Chemical equation:
2H₂O → 2H₂ + O₂
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 17.0 g/ 18.016 g/mol
Number of moles = 0.944 mol
Now we will compare the moles of oxygen with water to know the theoretical yield of oxygen.
H₂O : O₂
2 : 1
0.944 : 1/2×0.944 = 0.472 mol
Mass of oxygen:
Mass = number of moles× molar mass
Mass = 0.472 mol × 32 g/mol
Mass = 15.104 g
Percent yield:
Percent yield = [Actual yield / theoretical yield] × 100
Percent yield = [ 10.2 g/ 15.104 g] × 100
Percent yield = 0.675 × 100
Percent yield = 67.5%
We can use the magnification equation for this problem.
Magnification equation:
<em>hi/h0 = di/d0</em>
Where in <em>hi </em>: image size, <em>h0</em> : object size, <em>di </em>: image distance, <em>d0 </em>: object distance from mirror
So plugging in the given variables we will have the corresponding equation
0.1 m / 0.3 m = <em>di / </em>0.4 m
<em>di</em> = 0.1333333m
The generated image of the object is located 0.13 meters or 13 cm away from the mirror
