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Monica [59]
3 years ago
7

A substance undergoes a change. Which of the following indicates that the change was a chemical change?

Chemistry
2 answers:
JulijaS [17]3 years ago
7 0

Answer;

-New molecules formed

Explanation;

-Chemical changes are type of changes that occurs when substances combine to form a new substance. They occur as a result of chemical reaction. During a chemical reactions, the atoms within a substance are rearranged into different combinations.

-Examples of chemical changes include; rusting of iron, heating sugar to form caramel, baking a cake, digesting food among others.

valentina_108 [34]3 years ago
5 0
New molecules would form.
the other three are examples of a physical change
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Double Displacement Reaction

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How many significant numbers are there in 40.00
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Given:
bulgar [2K]

Answer:

The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Explanation:

Given;

CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol

From the combustion reaction above, it can be observed that;

1 mole of methane (CH₄) released 890 kilojoules of energy.

Now, we convert 59.7 grams of methane to moles

CH₄ = 12 + (1x4) = 16 g/mol

59.7 g of CH₄ = \frac{59.7}{16} = 3.73125 \ moles

1 mole of methane (CH₄) released 890 kilojoules of energy

3.73125 moles of methane (CH₄) will release ?

= 3.73125 moles x  -890 kJ/mol

= -3320.81 kJ

Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

5 0
3 years ago
If 36.2g of Acetic Acid (HC2H302) was dissolved in 300. mL of water, what is the
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The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.

36.2g \times \frac{1mol}{60.05g} = 0.603mol

Step 2: Convert the volume of solution to liters

We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)

300mL \times \frac{1L}{1000mL} = 0.300L

Step 3: Calculate the molarity of the solution

The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution

M = \frac{0.603mol}{0.300L} = 2.01 M

7 0
3 years ago
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