A 1430 kg car speeds up from 7.5 m/s to 11 m/s in 9.3 s. Ignoring friction, how much power did that require?
1 answer:
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Answer:
The drag coefficient is
Explanation:
From the question we are told that
The density of air is
The diameter of bottom part is
The power trend-line equation is mathematically represented as
let assume that the velocity is 20 m/s
Then
The drag coefficient is mathematically represented as
Where
is the drag force
is the density of the fluid
is the flow velocity
A is the area which mathematically evaluated as
substituting values
Then