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vlada-n [284]
3 years ago
9

The Starship Enterprise speeds past an asteroid at 0.920c. If an observer on the asteroid sees 10.0 seconds pass on her watch, h

ow long would that time interval be if measured by an observer on the Enterprise?
Physics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

25.52 seconds

Explanation:

Speed of space ship = 0.92 c = v

c = Speed of light

Time observed from asteroid = Δt = 10 seconds

Time dilation

\Delta t'=\frac{\Delta t}{\sqrt{1-\frac {v^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{10}{\sqrt{1-\frac {0.92^2c^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{10}{\sqrt{1-0.92^2}}\\\Rightarrow \Delta t'=25.52\ s

∴ Time interval be if measured by an observer on the Enterprise would be 25.52 seconds

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Explanation:

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