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SashulF [63]
3 years ago
13

Three laws of mechanics and

Physics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

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I have learned that the energy produced by moving electron is called
alex41 [277]
Answer:

kinetic energy

Explanation:

Electrical energy is a type of kinetic energy caused by moving electric charges. The amount of energy depends on the speed of the charges – the faster they move, the more electrical energy they carry.
6 0
3 years ago
If x=2/3and y=3/2, then find value of (x + y) divided by (x-y)<br><br>​
Reika [66]

Answer:

-13/5

Explanation:

13/6÷(-5/6)

-13/5

8 0
3 years ago
A 120 V electric heater draws a current of 14.1 A. What is the resistance, in ohms?
Sav [38]

Answer:

8.5 ohms

Explanation:

from ohms law

V=IR

120=14.1R

divide both sides by 14.1

120/14.1=14.1R/14.1

R=8.5ohms

5 0
3 years ago
Read 2 more answers
What is rectilinear propagation of light?​
nignag [31]

Answer:

Rectilinear propagation describes the tendency of electromagnetic waves to travel in a straight line. Light does not deviate when travelling through a homogeneous medium, which has the same refractive index throughout; otherwise, light suffers refraction.

3 0
3 years ago
Read 2 more answers
007 (part 1 of 2) 1.0 points
levacccp [35]

Answer:

a) The angle of refraction is approximately 34.7

b) The angle the light have to be incident to give an angle of refraction of 90° is approximately 53.42°

Explanation:

According to Snell's law, we have;

\dfrac{n_1}{n_2} = \dfrac{sin (\theta_2)}{sin (\theta_1)}

The refractive index of the glass, n₁ = 1.66

The angle of incident of the light as it moves into water, θ₁ = 27.2°

a) The refractive index of water, n₂ = 1.333

Let θ₂ represent the angle of refraction of the light in water

By plugging in the values of the variables in Snell's Law equation gives;

\dfrac{1.66}{1.333} = \dfrac{sin (\theta_2)}{sin (27.2^{\circ})}

sin (\theta_2) = sin (27.2^{\circ}) \times \dfrac{1.66}{1.333} \approx 0.5692292265

θ₂ = arcsin(0.5692292265) ≈ 34.7°

The angle of refraction of the light in water, θ₂ ≈ 34.7°

b) When the angle of refraction, θ₂ = 90°, we have;

\dfrac{1.66}{1.333} = \dfrac{sin (90^{\circ})}{sin (\theta_1)}

sin (\theta_1) = \dfrac{sin (90^{\circ})}{\left( \dfrac{1.66}{1.333}\right)} = sin (90^{\circ}) \times \dfrac{1.333}{1.66} \approx 0.803

θ₁ ≈ arcsin(0.803) ≈ 53.42°

The angle of incident, θ₁, that would give an angle of refraction of 90° is θ₁ ≈ 53.42°

3 0
3 years ago
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