If you stay on the same planet and drop a lot of objects one at a time,
it turns out that every object you drop falls from your hand to the ground
with the same acceleration, and hits the ground with the same speed,
no matter whether the object is light, heavy, or anything in between.
That particular value of acceleration is the "acceleration due to gravity".
On Earth, it's 9.81 meters per second². On the moon, it's 1.62 meters
per second². On Jupiter, it's 25.89 meters per second².
Why we don't generally notice it: The previous description is true if the
ONLY force on the object is the force of gravity. If it has to fall through
<u>air</u> on the way down, then the air can have a great effect on it. Many
museums have an exhibit where they drop things in a long tube with
all the air removed from it, and there you can see some pretty weird
stuff ... like a bowling ball, a rock, a sheet of paper, and a feather, all
falling together, with nothing fluttering.
<u>Why</u> everything falls with the same acceleration ? That's a separate question.
The universal gravity formula is <span>F = G(Me)(Mm)/r^2. Lets use this formula to help us calculate what would happen if the Moon was twice as big.
</span><span>Mn = new mass = 2*Mm
</span><span>Fn = G(Me)(Mn)/r^2
</span><span>Fn = G(Me)(2Mm)/r^2
</span>Fn = 2*G(Me)(Mm)/r^2
<span>Fn = 2*F
</span>So 2 times the force it was before. The force should be the same, but you never know the moon and space as well know it can work in very mysterious ways.
Daniel applies a 30 Newtons force on the ball that sends the ball 300 meters, which gives the work done by Daniel as 9 kJ
<h3>How can the work done be obtained from the given force and distance?</h3>
The given parameters are;
The force with which Daniel hit the ball = 30 Newtons
The distance the ball flew, following the application of the force = 300 meters
Required;
The amount of work done on the ball by Daniel
Solution:
- Work done = Force applied × Distance moved in the direction of the force
Therefore;
The work done by Daniel on the ball, <em>W</em>, can be calculated as follows;
W = 30 N × 300 m = 9000 J = 9 kJ
- The work done by Daniel on the ball is 9 kJ
Learn more about work energy and power here:
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I’m pretty sure one increases just straight up velocity and the other is kind of a deceleration
Answer:
4750000 J
Explanation:
Kinetic Energy= 1/2* mass* velocity²
1/2*950*100²=4750000