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svp [43]
3 years ago
8

What causes the moon's phases?

Physics
2 answers:
Anon25 [30]3 years ago
3 0
The answer is:  [D]:  "the position of the moon each month in relation to THE SUN AND THE MOON" .
______________________________________________________
   Note of interest:  The origin of the word "month" was:  "moon-th" — but shortened to "month" — (no coincidence!).
______________________________________________________
rjkz [21]3 years ago
3 0

C.

Changes in how much of the sunlit side of the moon faces Earth

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A car passes you at 18 m/s to the north and increases its speed at a rate of 3.0 m/s. Determine the car's velocity when it has a
monitta

122

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8 0
3 years ago
Which causes an object to have inertia
Vikentia [17]
That's a pretty slippery topic. I think the big brains and high-power cosmologists can spend a month discussing it and not have an answer.

For US ... people who are not big brains or high-power cosmologists ...
I think the best way to think about it is that MASS causes inertia.

The more mass an object has, the more inertia it has. And all of the
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7 0
3 years ago
Instruction
Simora [160]

According to Edge, the answers is

<h3>3100 V</h3>

and

<h3>200v</h3>

4 0
3 years ago
10. A 90 kg box is sliding across a surface at a constant velocity while experiencing a rightward applied
ANEK [815]

If the box is moving at constant velocity, net force must be zero, so:

F + fr = 0

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4 0
3 years ago
Read 2 more answers
A ball with a mass of 275 g is dropped from rest, hits the floor, and re-bounds upward. If the ball hits the floor with a speed
disa [49]

Answer:

a) \Delta p = 1.350\,\frac{kg\cdot m}{s}, b) \Delta p' = -0.454\,\frac{kg\cdot m}{s}, c) D. The magnitud of the change in the ball's momentum.

Explanation:

a) The magnitude of the change in the ball's momentum is:

\Delta p = (0.275\,kg)\cdot \left[\left(1.63\,\frac{m}{s} \right)-\left(-3.28\,\frac{m}{s} \right)\right]

\Delta p = 1.350\,\frac{kg\cdot m}{s}

b) The change in the magnitude of the ball's momentum:

\Delta p' = (0.275\,kg)\cdot \left[(1.63\,\frac{m}{s} )-(3.28\,\frac{m}{s} ) \right]

\Delta p' = -0.454\,\frac{kg\cdot m}{s}

c) The magnitude of the change in the ball's momentum is more directly related to the net force acting on the ball, as it measures the effect of the force on change in ball's motion at measured time according to the Impact Theorem. So, the right answer is option D.

3 0
4 years ago
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