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2 years ago

What causes the moon's phases?

2 answers:

3 0

The answer is: [D]: "the position of the moon each month in relation to THE SUN AND THE MOON" .
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Note of interest: The origin of the word "month" was: "moon-th" — but shortened to "month" — (no coincidence!).
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rjkz [21]2 years ago

3 0

Changes in how much of the sunlit side of the moon faces Earth

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Which countries were considered the three major Axis Powers?

7nadin3 [17]

B. JAPAN, GERMANY, and ITALY

The main Axis powers were Japan, with Emperor Hirohito as leader; Germany, with Adolf Hitler as leader; and Italy, with Benito Mussolini as leader. They were all dictators.

The Axis powers began to form in 1936

15th October 1936 - Germany and Italy signed a friendship treaty - Rome-German Axis.
25th November 1936 - Germany and Japan signed a treaty against communism - Anti-Comintern Pact

22nd May 1939 - Germany and Italy signed a stronger alliance - Pact of Steel
27th September 1940 - Japan signed the Pact of Steel - It became known as the Tripartite Pact.

8 0

2 years ago

Would you be doing more work by going up the stairs twice as fast?

True [87]

Yes you would be doing more work

5 0

2 years ago

Read 2 more answers

HELP!!! I will 5 star if its helpful :(

victus00 [196]

Answer:

Net Force Formula: F1+F2+F3...+FN

*(MAKE SURE YOU MAKE NOTE OF THE NEGATIVE FORCES AND SUBTRACT THEM!)*

Explanation:

Top left: 17N+25N+25N-42N= 25N

Top right: 65N+200N-65N-150N-200N= 150N

Bottom left: 189N+123N+284N-96N-188N-312N= 0N

Bottom right: 34N+77N-12N-34N= 65N

I hope this helps! :))

5 0

3 years ago

A 20.0 μf capacitor is charged to a potential difference of 850 v. the terminals of the charged capacitor are then connected to

liberstina [14]

(a) $Q = 1.70\times 10^{-2}\;\text{C}$ ;
(b) $V_\text{final} = 5.31\times 10^{2}\;\text{V}$ ;
(c) $E_\text{final} = 4.52\;\text{J}$ ;
(d) $\Delta E = 2.82\;\text{J}$ .

All four values are in 3 sig. fig.

<h3>Explanation</h3>

(a)

$Q = C\cdot V = 20.0\times 10^{-6} \times 850\;\text{V} = 1.70\times 10^{-2}\;\text{J}$ .

(b)

Sum of the final charge on the two capacitors should be the same as the sum of the initial charge. Voltage of the two capacitors should be the same. That is:

$C_1\cdot V_\text{final} +C_2 \cdot V_\text{final} = C_1\cdot V_\text{initial}$ ;

$(C_1+C_2)\cdot V_\text{final} = C_1\cdot V_\text{initial}$ ;

$\displaystyle V_\text{final} = \frac{C_1}{C_1+C_2}\cdot V_\text{initial}\\\phantom{V_\text{final}} = \frac{20.0\;\mu\text{F}}{20.0\;\mu\text{F} + 12.0\;\mu\text{F}} \times 850\;\text{V}\\\phantom{V_\text{final}} =531\;\text{V}$ .

(c)

$\displaystyle E = \frac{1}{2}\cdot C\cdot V^{2}$ .

$\displaystyle E_\text{final} = \frac{1}{2} (C_1 + C_2) \cdot {V_\text{final}}^{2} \\\phantom{E_\text{final}} = \frac{1}{2} \times (20.0\times 10^{-6} + 12.0\times 10^{-6}) \times 531.25\\\phantom{E_\text{final}} = 4.52\;\text{J}$ .