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Montano1993 [528]
3 years ago
13

Identify the compound. Which of these is a compound?

Chemistry
2 answers:
STatiana [176]3 years ago
8 0

Answer: Image 3 is a compound.

Explanation: A compound is something that consists of two or more  different elements bonded chemically.

A molecule is formed when two or more elements combine chemically.

An element is described as something which cannot be broken down by any chemical means.

We are given 4 images.

Image 1 is an element as it is showing the shell structure of Oxygen (O) element.

Image 2 is an element as only 1 element is known that is Magnesium (Mg).

Image 3 is a compound as in the structure 2 elements are shown which is bonded together. Elements present in this are Carbon (C) and Oxygen (O).

Image 4 is a molecule as in the structure 2 H-atoms combine chemically, but it cannot be considered as compound as the two elements are not different.

Bond [772]3 years ago
7 0
The answer has to be either CO2 or mg. But i am not sure which one 
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The standard enthalpy of formation of methanol is, -238.7 kJ/mole

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The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0
3 years ago
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