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madreJ [45]
3 years ago
8

Dr. Ray has developed a new way to remove oil from wetlands in the event of an oil spill. To test his new process, Dr. Ray build

s a scale model of a wetland in his lab and pours a small amount of oil into it. He then observes the rate at which his process is able to remove the oil from the model. Why did Dr. Ray use a model? A. Because dumping oil in a real wetland would be dangerous. B. Because real wetlands are too complicated for his process to work. C. Because his model makes the process more complicated. D. Because real wetlands are too large to be affected by oil.
Chemistry
2 answers:
DiKsa [7]3 years ago
6 0

A scientific model is a pictorial, graphical or theoretical representation of any complex process or idea that is being studied. Any process that cannot be studied directly or that would cause an environmental issue, is studied by building up a model. In the given model, Dr. Ray built a scale model of a wetland to poured some oil to study the rate at which the oil is removed from the model. It would be difficult to study the phenomenon in wetland directly as pouring oil in the wetland would be dangerous to the plant and animal species present in the wetland.

Therefore, the correct option would be A. Because dumping oil in a real wetland would be dangerous.

Vsevolod [243]3 years ago
4 0

Answer:

A. Because dumping oil in a real wetland would be dangerous.

Explanation:

I did the Quiz and got it correct.

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4 years ago
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The density of lead is 11.3 g/cm. What is the mass of a cube of lead with 10.0 cm on each edge? Show work please.​
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3 years ago
What is the [OH-] of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 m
velikii [3]

Answer: The [OH^-] of a solution is 10^{-12} M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of HCl = \frac{\text {given mass}}{\text {Molar mass}}=\frac{0.0912g}{36.5g/mol}=0.0025mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.0025\times 1000}{250}=0.01

pH or pOH is the measure of acidity or alkalinity of a solution.

HCl\rightarrow H^++Cl^{-}

According to stoichiometry,

1 mole of HCl gives 1 mole of H^+

Thus 0.01 moles of HCl gives =\frac{1}{1}\times 0.01=0.01 moles of H^+

Putting in the values:

[H^+][OH^-]=10^{-14}

[0.01][OH^-]=10^{-14}

[OH^-]=10^{-12}

Thus the [OH^-] of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 ml of solution is 10^{-12} M

8 0
4 years ago
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3 years ago
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C. Electron Energy Level or Cloud

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