Answer:
full octets live in noble gas world so you need to be whatever your charge is away from there in steps on the periodic table so s-1 is the one that falls short as it is 2 moves away from Ar which is its closest Noble gas
Explanation:
Answer:
The expression for the number of moles is 5.0 g / 56 g/mol
Explanation:
The mole is the amount of substance that contains as many entities as there are carbon atoms in 12 grams of a carbon-12 isotope. It is the amount of a substance that contains the same number of units as the number of atoms in 12g of carbon - 12 isotope. A mole of an ionic substance contains 6.02 * 10^23 atoms of the element. Mathematically, moles is the mass of a substance in grams divided by the relative molecular mass.
Moles = mass / relative molecular mass
In the given question, mass = 5.0 g
Molecular mass of CaO ( Ca= 40, O = 16) = ( 40 + 16) g/mol = 56 g/mol
Moles = 5.0 g/ 56 g/mol is the expression for the number of moles in 5.0 g of CaO
Time such as minutes, days, and months will always be a(n)....... INDEPENDENT variable
"if it is tested in a controlled setting with repeated results" is the statement among the choices given in the question that best describes that can possibly make this scientific claim valid. The correct option among all the options that are given in the question is the first option or option "A". I hope the answer has helped you.<span>
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Answer:
16.4 °C
Explanation:
Boiling point elevation is the phenomenon in which the boiling point of a solvent will increase when another compound is added to it; meaning that athe resultant solution has a higher boiling point than its pure solvent.
Using the ebullioscopic constant,
ΔT = m * i * Kb
Where,
Δ T is the temperature difference between the boiling point of the solution, Temp.f and boiling point of the pure solvent, Temp.i
Kb is the ebulliscope factor of water = 0.510 °C.kg/mol
i is the van hoffs number = 1
m is the molality in mol/kg.
Calculating the molality of the solution,
Temp.i = 100°C
Temp.f = 104.5 °C
= 4.5/(1*0.510)
= 8.8235 mol/kg
Freezing point depression is defined as the decrease in the freezing point of a solvent on the addition of a solute.
Using the same equation, but kf = 1.86 °C.kg/mol
ΔT = m * i * Kf
Temp.i = freezing point of water = 0°C
Temp.f = (8.8235*1.86) - 0
= 16.412 °C
Freezing point of the solution = 16.4 °C