Hi pupil here's your answer ::
_____________________________
How does Newton's second law of motion gives the measurement of force?
So the answer is first : what is newton's second law? =》The rate of change of momentum of an object is equivalent to particular direction of the FORCE
=> This is how Newton's second law of motion gives the measurement of FORCE .
=>It gives measurement as the equation
》 F=MA《
Where F is force , M is mass of the object , and A is the acceleration produced .
_____________________________
hope that it helps. . . . . .
Answer:
Originally : Level = log I / I0
Currently: Level = 10 log I / I0
Level = 10 log 600 = 10 * 2.78 = 27.8
Note the term 1 bel = 10 decibels
Answer:
<h2>The angular velocity just after collision is given as</h2><h2>
</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>
Explanation:
As per given figure we know that there is no external torque about hinge point on the system of given mass
So here we will have
now we can say
so we will have
Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass
So we can use angular momentum conservation about the hinge point
Answer:
b. able to travel through a vacuum.
Explanation:
The most distinguishing factor of an electromagnetic waves is that they are able to travel through a vacuum.
These waves do not require materials in a medium for propagation.
- Electromagnetic waves are formed by the propagation of the electric and magnetic fields.
- They vibrate at an angle of 90° .
- They are unlike like mechanical waves that requires that requires materials in medium for their propagation.
Answer:
7.78x10^-8T
Explanation:
The Pointing Vector S is
S = (1/μ0) E × B
at any instant, where S, E, and B are vectors. Since E and B are always perpendicular in an EM wave,
S = (1/μ0) E B
where S, E and B are magnitudes. The average value of the Pointing Vector is
<S> = [1/(2 μ0)] E0 B0
where E0 and B0 are amplitudes. (This can be derived by finding the rms value of a sinusoidal wave over an integer number of wavelengths.)
Also at any instant,
E = c B
where E and B are magnitudes, so it must also be true at the instant of peak values
E0 = c B0
Substituting for E0,
<S> = [1/(2 μ0)] (c B0) B0 = [c/(2 μ0)] (B0)²
Solve for B0.
Bo = √ (0.724x2x4πx10^-7/ 3 x10^8)
= 7.79 x10 ^-8 T
