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1 year ago

What occurs in the space when a massive object undergoes a change in its motion?

Physics

1 answer:

Lorico [155]1 year ago

7 0

Gravitational waves are emitted in the space when a massive object undergoes a change in its motion.

Gravitational waves are emitted. Bends spacetime, ripples travel outward from a gravitational source at the speed of light. The more massive the object and greater its acceleration, the stronger the resulting gravitational wave.

Therefore, A change in motion produces gravitational waves.

Definition of Gravitational waves:

Gravitational waves are disturbances or ripples in the curvature of spacetime, generated by accelerated masses, that propagate as waves outward from their source at the speed of light.

To learn more about Gravitational waves here

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A worker pushes horizontally on a 36.0 kg crate with a force of magnitude 112 N. The coefficient of static friction between the

Yuliya22 [10]

Answer:

value of fs,max under the circumstances is

f = 42.56 N

Explanation:

The formula is µ = f / N, where µ is the coefficient of friction, f is the amount of force that resists motion, and N is the normal force. Normal force is the force at which one surface is being pushed into another.

So f = µN

f = 0.380 * 112

f = 42.56 N

5 0

3 years ago

Read 2 more answers

Block A, with mass mA, is initially at rest on a horizontal floor. Block B, with mass mB, is initially at rest on the horizontal

nexus9112 [7]

Answer:

(E) μs(mA +mB)g

Explanation:

We can apply for mB:

∑ Fx = mB*a (→)

⇒ Ffriction = mB*a ⇒ a = Ffriction / mB = μs*N / mB

⇒ a = μs*(mB*g) / mB ⇒ a = μs*g (acceleration of the system)

Now, for mA we have

∑ Fx = mA*a (→)

F - Ffriction = mA*a ⇒ F = mA*a + Ffriction

⇒ F = mA*(μs*g) + μs*(mB*g) ⇒ F = μs*g*(mA + mB)

We must know that the friction acts only between the two blocks

8 0

3 years ago

I need help!!!! I don’t understand physical science at all.

allochka39001 [22]

B is the correct answer

3 0

2 years ago

A force F is used to raise a 4-kg mass M from the ground to a height of 5 m. What is the work done by the force F? (Note: sin 60

miskamm [114]

Answer:

Answer:196 Joules

Explanation:

Hello

Note: I think the text in parentheses corresponds to another exercise, or this is incomplete, I will solve it with the first part of the problem

the work is the product of a force applied to a body and the displacement of the body in the direction of this force

assuming that the force goes in the same direction of the displacement, that is upwards

W=F*D (work, force,displacement)

the force necessary to move the object will be

$F=mg(mass *gravity)\\F=4kgm*9.8\frac{m}{s^{2} }\\ F=39.2 Newtons\\replace\\\\W=39.2 N*5m\\W=196\ Joules$

Answer:196 Joules

I hope it helps

5 0

3 years ago

Two violinists are trying to play in tune. However, whenever they play their A string at the same time they hear a beat frequenc

kaheart [24]

Answer:

The possible frequencies for the A string of the other violinist is 457 Hz and 467 Hz.

(3) and (4) is correct option.

Explanation:

Given that,

Beat frequency f = 5.0 Hz

Frequency f'= 462 Hz

We need to calculate the possible frequencies for the A string of the other violinist

Using formula of frequency

$f'=f_{1}-f$ ...(I)

$f'=f_{1}+f$ ...(II)

Where, f= beat frequency

f₁ = frequency

Put the value in both equations

$f'=462-5=457\ Hz$

$f'=462+5=467\ Hz$

Hence, The possible frequencies for the A string of the other violinist is 467 Hz and 457 Hz.

4 0

3 years ago