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gogolik [260]
4 years ago
13

What are the results from a stream leaving a mountain range and flowing into a lowland. select all that apply?

Physics
2 answers:
Delvig [45]4 years ago
4 0

The flow slows down, the amount of sediment has decreased, and large amounts are deposited at the foot of the mountain

Vera_Pavlovna [14]4 years ago
3 0
The rate of the flow speeds up 
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1. It takes a 25 N force to push a 250 N box across the floor.
Fed [463]

Answer:

A:- 50 J

B:- 500 J

Explanation:

a) Given that a 25 N force is applied to move the box. Also the floor is having friction surface.

So in order to move the box, the floor should have friction of atleast 25 N.

∴ friction = 25 N

Work done = force * displacement of box

Given, the box is moved 2 m across the floor

So, Work done = friction * 2 m

                         = 25 * 2

                         = 50 J

b) Given, the box is having weight of 250 N weight

Gravitational force is acting on the box which is equal to (mass * gravity)

∴ Force = 250 N

The box is lifted 2 m above the floor.

So, displacement = 2 m

Work done = force * displacement of box

Work done = 250 * 2

                   = 500 J

5 0
3 years ago
The total of 8 and 13
Stella [2.4K]
The total is 21. If you use a calculator or count with your fingers it can help make the answer easier so in the end you will get 21 as your total.


7 0
3 years ago
Read 2 more answers
Willy the heat Willy the Lol​
mr_godi [17]

Explanation:

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4 0
3 years ago
Read 2 more answers
A steel plate weighing 180 lb with center of gravity at point G is supported by a roller at point A, a bar DE, and a horizontal
melamori03 [73]

Answer:

Therefore, the force supported  by the hydraulic cylinder is = -70.01 lb

Thus, the force supported by the bar = -233.84 lb

The reaction force supported by the reaction of the roller = 341.31 lb

Explanation:

The attached diagrams is shown in the file below:

From there; taking moments about point A

\sum M__A }=0

- 40 (180) - (80) F_E Cos 37° + 55  

-7200 + F_E (-80 Cos 37° + 55 sin 37° ) = 0

= - 7200 - 30.79  F_E

- 30.79  F_E = 7200

F_E = -\frac{7200}{30.79}

F_E  = -233.84 lb

Thus, the force supported by the bar = -233.84 lb

Taking the equilibrium of forces in the vertical direction

\sum f_y = 0

F_E sin 37 + F_A cos 20 - F_G = 0

- 233.84 sin 37 + F_A cos 20 - 180 = 0

F_A cos 20  = 320.73

F_A = \frac{320.73}{cos 20}

F_A = 341.31 lb

The reaction force supported by the reaction of the roller = 341.31 lb

Taking the equilibrium of forces on the horizontal direction.

\sum f_y = 0

F_E cos 37 - F_{CB} + F_A sin 20° = 0

-233.84 cos 37 - F_{CB} + 341.31 sin 20° = 0  

-186.75 -  F_{CB} + 116.74 = 0

-  F_{CB} -70.01 = 0

-  F_{CB} = 70.01

F_{CB} = - 70.01 lb

Therefore, the force supported  by the hydraulic cylinder is = -70.01 lb

7 0
4 years ago
a lamp hangs from the ceiling at the height of 2.9 m. if the lamp breaks and falls to the floor what is its impact speed
nydimaria [60]
This is a problem that can be solved using free-fall motion analysis. Since the displacement (2.9m) is given, we can use the following equation to solve for the impact speed:

V^2 = 2gh

V = sqrt (2*9.8*2.9)
V = 7.54 m/s
5 0
4 years ago
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