<span>The
balanced half-reaction: V</span>⁺(aq) → V⁵⁺(aq) + 4e⁻.
Vanadium(I) cations lose four electrons and became vanadium(V) cations.
<span>
Oxidation reaction is increasing of oxidation number of element, because
element or ion lost electrons in chemical reaction.
Reduction is lowering oxidation number because element or ions gain
electrons.</span>
Answer:
Vaporization
Since the question does not specify what molecule is being acted upon by the increment in temperature, I'll assume it's water.
When first taken out of the fridge, water is in the form of ice, and it has not been affected by a change in temperature yet, so it's at the origin.
(origin = ice)
As you raise the temperature, however, the ice starts to melt, and melting occur during phase 2. You have to keep the temperature constant for the process to properly occur.
(phase 2 = melting)
After it finishes melting, the ice is now in it's liquid state, which is water. The temperature continues to rise in order to proceed to the next phase.
(2nd slope = water)
Lastly, Water is being vaporized during phase 4. Notice, the temperature is kept constant in order to allow the process to properly occur.
(phase 4 = vaporization)
Answer:
C, <u>The presence of secondary xylem as wood tissue.</u>
Explanation:
The presence of secondary xylem as wood tissue. While this strengthens a plant and allows it to grow taller, it does not directly help a plant to spread.
To determine the volume of chlorine gas that is needed, we need to first know the reaction. It is expressed as follows:
2Na + Cl2 = 2NaCl
Then, from the amount of NaCl to be produced, we calculate the moles of Cl2 needed.
14.2 g NaCl ( 1 mol / 58.44 g ) ( 1 mol Cl2 / 2 NaCl ) = 0.1215 mol Cl2
To determine the volume of the gas, we need an equation that would relate the number of moles to volume. There are a number of equation available but some are complex equations so we assume that it is an ideal gas. We use the equation:
PV = nRT
V = nRT / P
V = 0.1215 mol ( 0.08205 L-atm / mol-K ) (45.3 +273.15 K) / 1.72 atm
V = 1.85 L Cl2 gas
