Answer:
42.69 N and 18.07 N
Explanation:
We are given that
Mass of ladder=6.2 kg
Length of ladder=1.97 m
Distance of Sawhorse A from one end=0.64 m
Distance of sawhorse B from other end=0.17 m
Let center of Ladder=![\frac{1.97}{2}=0.985 m](https://tex.z-dn.net/?f=%5Cfrac%7B1.97%7D%7B2%7D%3D0.985%20m)
Now, the distance of sawhorse A from center=r=0.985-0.64=0.345 m
Distance of sawhorse B from center of ladder=0.985-0.17=0.815 m
Force one ladder due to gravity=mg=![6.2\times 9.8=60.76N](https://tex.z-dn.net/?f=6.2%5Ctimes%209.8%3D60.76N)
Where ![g=9.8 m/s^2](https://tex.z-dn.net/?f=g%3D9.8%20m%2Fs%5E2)
Torque applied on Sawhorse A=![0.345F_a](https://tex.z-dn.net/?f=0.345F_a)
Torque applied on Sawhorse B=![0.815F_b](https://tex.z-dn.net/?f=0.815F_b)
In equilibrium
![0.345F_a=0.815F_b](https://tex.z-dn.net/?f=0.345F_a%3D0.815F_b)
![F_b=\frac{0.345}{0.815}F_a](https://tex.z-dn.net/?f=F_b%3D%5Cfrac%7B0.345%7D%7B0.815%7DF_a)
Total force=![F_a+F_b](https://tex.z-dn.net/?f=F_a%2BF_b)
![F_a+\frac{0.345}{0.815}F_a=60.76](https://tex.z-dn.net/?f=F_a%2B%5Cfrac%7B0.345%7D%7B0.815%7DF_a%3D60.76)
![\frac{0.815F_a+0.345F_a}{0.815}=60.76](https://tex.z-dn.net/?f=%5Cfrac%7B0.815F_a%2B0.345F_a%7D%7B0.815%7D%3D60.76)
![\frac{1.16}{0.815}F_a=60.76](https://tex.z-dn.net/?f=%5Cfrac%7B1.16%7D%7B0.815%7DF_a%3D60.76)
![F_a=\frac{60.76\times 0.815}{1.16}=42.69 N](https://tex.z-dn.net/?f=F_a%3D%5Cfrac%7B60.76%5Ctimes%200.815%7D%7B1.16%7D%3D42.69%20N)
![F_b=\frac{0.345}{0.815}\times 42.69=18.07 N](https://tex.z-dn.net/?f=F_b%3D%5Cfrac%7B0.345%7D%7B0.815%7D%5Ctimes%2042.69%3D18.07%20N)
Answer: 3MW
Explanation:
W = 1/2 mv^2
W = 0.5 x 1200 x 25^2 = 375 kW
T = 8s
P= 335 x 10^3 x 8 = 3,000 kW = 3MW
Answer:
Animal Cells
Explanation:
they dont have cell walls because they dont need them. Wall cells are found in plants, which animals dont need.
Answer:
Explanation:
Given
velocity of antelope ![v=10 m/s](https://tex.z-dn.net/?f=v%3D10%20m%2Fs)
antelope needs to cover a horizontal distance of 20 m
considering horizontal velocity antelope needs to cover 20 m in t sec which is given by
![t=\frac{20}{10}=2 s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B20%7D%7B10%7D%3D2%20s)
i.e. in 2 sec antelope needs to jump and return to ground for zero vertical displacement
![h=ut+\frac{1}{2}at^2](https://tex.z-dn.net/?f=h%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
h=vertical displacement
a=acceleration
t=time
for,
, t=1 s
![h_{max}=0+\frac{1}{2}g(1)^2](https://tex.z-dn.net/?f=h_%7Bmax%7D%3D0%2B%5Cfrac%7B1%7D%7B2%7Dg%281%29%5E2)
![h_{max}=\frac{g}{2}](https://tex.z-dn.net/?f=h_%7Bmax%7D%3D%5Cfrac%7Bg%7D%7B2%7D)
![h_{max}=4.9 m](https://tex.z-dn.net/?f=h_%7Bmax%7D%3D4.9%20m)
The solar interior includes the core, radiative zone and convective zone. The photosphere is the visible surface of the Sun.
So the answers should be:
<u>A) Photosphere C) Core D) Radioactive zone </u>and<u> F) Convective zone.</u>
I hope this helps. Sorry if I made any mistakes. :)