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ozzi
3 years ago
12

How do you use multiplication to find the perimeter of a square

Mathematics
2 answers:
bogdanovich [222]3 years ago
8 0
Since a square has 4 equal sides, you can take the base x the height. So if your square is a 4x4, you can just multiply 4 x 4. It would be the same as adding 4+4+4+4
scoundrel [369]3 years ago
7 0
Multiply 4 by the length of a side
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Is 0.002475 rational or irrational?
pickupchik [31]
I think the answer is irrational
8 0
3 years ago
Read 2 more answers
Line AB and line CD intersect at point E, with point E between A and B and between C and D. Which rays are opposite rays?
olchik [2.2K]

Answer:

EA, EB, EC and ED are opposites rays.

Step-by-step explanation:

Given that,

Line AB and line CD intersect at point E.

According to figure,

We need to find opposite rays

Using diagram

We draw a first line AB and second line CD which is intersect of AB at point E.

Now, EA and EB is called opposite ray of first line AB.

Similarly,

EC and ED is called opposite ray of first line CD.

Hence, EA, EB, EC and ED are opposites rays.

3 0
3 years ago
Find the value of x and y <br> (5y-23) <br> (2x+13)<br> (3x)<br> 47
liq [111]

Answer:

x = 24

y = 19

Step-by-step explanation:

7 0
3 years ago
8t=56 plsssssss helppp mee
k0ka [10]
8t = 56
t = 56/8
t = 7
5 0
3 years ago
Read 2 more answers
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
4 years ago
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