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alexira [117]
3 years ago
12

Calculate the volume of 2.0116 x 10^23 molecules of nh3 gas trapped in a container at a pressure of 2280.0 mmhg and a temperatur

e of 41.000 c
Chemistry
1 answer:
OLEGan [10]3 years ago
5 0
The problem in this question can be solved using the ideal gas formula. Ideal gas formula show interaction between the pressure, volume, temperature and the number of molecules.

n= number of molecule/ avogadro number
n= (2.0116 x 10^23 / 6.02*10^23)= 1/3 mole

T= celcius + 273.15
T= (41+273.15) K=314.15

P=2280 mmHg / (760mmHg/atm)= 3 atm

PV=nRT
V= nrT/ P
V=  1/3 moles * (<span>0.08205 L atm / mol·K) </span>  * 314.15 K / 3 atm
V= 2.864 L
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describe in general terms an experiment to determine the molal freezing point depression constant kf of water. Assume the availa
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A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
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3 0
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The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 Right a
yuradex [85]

The moles of I₂ will form from the decomposition of 3.58g of NI₃ is 0.0136 moles.

<h3>How we calculate moles?</h3>

Moles of any substance will be calculated as:

n = W/M, where

W = required mass

M = molar mass

Given chemical reaction is:

2NI₃ → N₂ + 3I₂

Moles of 3.58g of NI₃ will be calculated as:

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To know more about moles, visit the below link:

brainly.com/question/15303663

8 0
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