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kirza4 [7]
3 years ago
6

Melissa wants to separate a mixture of many tiny beads that are all the same size. Some of the beads are made from pine wood and

some of the beads are metal.
What would be the easiest way for her to separate the mixture?

A. Add water and the wooden beads will dissolve.
B. Add water and the wooden beads will float.
C. Sift the beads and the wooden ones will stay on top.
D. Pick out all the wooden beads by hand.
Chemistry
2 answers:
Volgvan3 years ago
5 0

Answer:

Your answer here is B. Add water and the wooden beads will float.

Explanation:

Please mark me as Brainliest! :)

Serjik [45]3 years ago
3 0

B. Add water and the wooden beads will float.
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The ph scale for acidity is defined by ph=−log10[h+] where [h+]is the concentration of hydrogen ions measured in moles per liter
Leokris [45]

The question is incomplete.

The complete question probably is

The pH scale for acidity is defined by pH = − log₁₀[H⁺] where [H⁺] is the concentration of hydrogen ions measured in moles per liter (M). A solution has a pH of 2.55. Find the hydrogen ion concentration.

Answer: -

0.003 M

Explanation: -

pH = − log₁₀[H⁺]

Thus the hydrogen ion concentration [H⁺] = 10^{-pH}

= 10^{-2.55}

= 0.003 M

7 0
3 years ago
A sample of 8.00 g of Mg(OH)2 is added to 24.2 mL of 0.205 M HNO3. How many moles of Mg(OH)2 our present after the reaction is c
kogti [31]

The amount of Mg(OH)2  present after the reaction is complete is 0.136 moles of Mg(OH)2.

The equation of the reaction is;

2HNO3(aq) + Mg(OH)2(aq) -------> Mg(NO3)2(aq) + 2H2O(l)

Number of moles of Mg(OH)2 = 8.00 g/58 g/mol = 0.138 moles

Number of moles of HNO3 = 0.205 M × 24.2 mL/1000 = 0.00496 moles

Given that;

2 moles of HNO3 reacts with 1 mole of Mg(OH)2

0.00496 moles of HNO3 reacts with 0.00496 moles ×  1 mole /2 moles = 0.00248 moles of Mg(OH)2

Hence, Mg(OH)2 is the reactant in excess.

The amount of Mg(OH)2 remaining = Amount present - Amount reacted

Hence; 0.138 moles - 0.00248 moles = 0.136 moles of Mg(OH)2

Learn more: brainly.com/question/9743981

6 0
2 years ago
Sodium electron configuration unabbreviated
Tema [17]

Answer: [Ne] 3s¹

Explanation:

6 0
3 years ago
Which scientist is created with developing the first scientific atomic theory
Alona [7]
John Dalton was the first scientist
8 0
3 years ago
Lithium has two stable isotopes with masses of 6.01512 amu and 7.01600 amu. The average molar mass of Li is 6.941 amu. What is t
Dvinal [7]

Answer :  The percent abundance of Li isotope-1 and Li isotope-2 is, 6.94 % and 93.1 % respectively.

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of Li isotope-1 be 'x' and the fractional abundance of Li isotope-2 will be '100-x'

For Li isotope-1 :

Mass of Li isotope-1 = 6.01512 amu

Fractional abundance of Li isotope-1 = x

For Li isotope-2 :

Mass of Li isotope-2 = 7.01600 amu

Fractional abundance of Li isotope-2 = 100-x

Average atomic mass of Li = 6.941 amu

Putting values in equation 1, we get:

6.941=[(6.01512\times x)+(7.01600\times (100-x))]

By solving the term 'x', we get:

x=694.048

Percent abundance of Li isotope-1 = \frac{694.048}{100}=6.94\%

Percent abundance of Li isotope-2 = 100 - x = 100-6.94 = 93.1 %

6 0
3 years ago
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