The correct option is ARGON.
To quickly find out the element that is been described by the electronic configuration, write down and add together all the index figures in the electronic configuration. The index figures in the above electronic configuration are 2, 2, 6, 2 and 6. If you add all these figures together, you will get 18 and the element that has the atomic number of 18 is argon.
Answer:
Because burning a non-renewable resource that is not good for the atmosphere, will always cause some kind of chemical reaction to happen.
Examples of these reactions are...
- Acid rain, a very dangerous disaster.
- Global warming.
- Carbon increases.
Explanation:
in it I mass=150g,initial temp 1=95,mass2=500g,temp2=?,final temperature=27.2 C1=0.444C2=4.18
using formula
m1c1(final temp-initial temp1) =m2c2(temp2-final temp)
150x0.444(27.2-95)=500x4.18(?-27.2)
66(-67.8)=2000(?-27.5)
-4474.8=2000?-55000
collect like terms
-4474.8+55000=2000?
50525=2000?
divide both sides by 2000
2000?/2000=50525/2000
initial temperature =25.26 degree Celsius
Answer:
Final volume after applying 880 mmHg pressure = 89.28
Explanation:
Initial volume (V 1)= 100 ml
Initial pressure (P1) =780 mm Hg = 780/780 = 1atm
Final pressure (P2)=880 mm Hg = 880/780 =1.12 atm
Final volume (V2)=?
We know that,
Applying Boyle's law,
P1 V1=P2 V2
1*100=1.12*V2
100=1.12*V2
100/1.12=V2
89.28=V2
V2=89.28 ml
Hope this helps you. Please mark me as a brainlist.
a. pH=2.07
b. pH=3
c. pH=8
<h3>Further explanation</h3>
pH=-log [H⁺]
a) 0.1 M HF Ka = 7.2 x 10⁻⁴
HF= weak acid
![\tt [H^+]=\sqrt{Ka.M}\\\\(H^+]=\sqrt{7.2.10^{-4}\times 0.1}\\\\(H^+]=8.5\times 10^{-3}\\\\pH=3-log~8.5=2.07](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7BKa.M%7D%5C%5C%5C%5C%28H%5E%2B%5D%3D%5Csqrt%7B7.2.10%5E%7B-4%7D%5Ctimes%200.1%7D%5C%5C%5C%5C%28H%5E%2B%5D%3D8.5%5Ctimes%2010%5E%7B-3%7D%5C%5C%5C%5CpH%3D3-log~8.5%3D2.07)
b) 1 x 10⁻³ M HNO₃
HNO₃ = strong acid
![\tt pH=-log[1\times 10^{-3}]=3](https://tex.z-dn.net/?f=%5Ctt%20pH%3D-log%5B1%5Ctimes%2010%5E%7B-3%7D%5D%3D3)
c) 1 x 10⁻⁸ M HCl
![\tt pH=-log[1\times 10^{-8}]=8](https://tex.z-dn.net/?f=%5Ctt%20pH%3D-log%5B1%5Ctimes%2010%5E%7B-8%7D%5D%3D8)
