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forsale [732]
2 years ago
8

An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I

f the distance the electron travels through the field is 1.0 cm, how far is it deviated (Y) in its path when it emerges from the electric field? (me = 9.1 ´ 10 - 31 kg, e = 1.6 ´ 10 - 19 C)
Physics
1 answer:
oksano4ka [1.4K]2 years ago
6 0

Answer:

The deviation in path is 4.39 \times 10^{-3}

Explanation:

Given:

Velocity v = 1 \times 10^{6} \frac{m}{s}

Electric field E = 500 \frac{V}{m}

Distance x = 1 \times 10^{-2} m

Mass of electron m = 9.1 \times 10^{-31} kg

Charge of electron q = 1.6 \times 10^{-19} C

Time taken to travel distance,

    t = \frac{x}{v}

    t = \frac{1 \times 10^{-2} }{1 \times 10^{6} }

    t = 10^{-8} sec

Acceleration is given by,

  F = qE

ma = qE

   a = \frac{qE}{m}

   a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }

   a = 8.77 \times 10^{13} \frac{m}{s^{2} }

For finding the distance, we use kinematics equations.

   y = vt + \frac{1}{2}  at^{2}

Where v = 0 because here initial velocity zero

   y = \frac{1}{2} at^{2}

   y = \frac{1}{2} \times  8.77 \times 10^{13 } \times (10^{-2} )^{2}

   y = 4.39 \times 10^{-3} m

Therefore, the deviation in path is 4.39 \times 10^{-3}

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Find the separation of two points on the Moon’s surface that can just be resolved by the 200 in. (= 5.1 m) telescope at Mount Pa
rewona [7]

Answer:

The separation of the 2 points should be 50.0 meters.

Explanation:

According to Rayleigh's scattering criteria the angular separation between 2 points to be resolved equals

\theta =1.22\cdot \frac{\lambda }{D}

Applying the given values we get

\theta =1.22\cdot \frac{550\times 10^{-9} }{5.1}=0.1316\times 10^{-6}rads

thus the linear separation equals L=\theta \times Distance

Applying the given values we get

L=0.1316\times 10^{-6} \times 3.8\times 10^{5}\times 10^{3}meters\\\\\therefore L=50.00metes

6 0
3 years ago
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Misha Larkins [42]

Answer: C. Both observation 1 and observation 2

Explanation: A geocentric model shows the stars and the sun and where they move to.

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8 0
2 years ago
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in a standing sound wave in a pipe, nodes are regions of ... what. could someone help? thanks so much ;)
GalinKa [24]

Answer:

In a standing sound wave in a pipe, nodes are regions of mean atmosphere pressure and low displacement.

5 0
2 years ago
Earth's neighboring galaxy, the Andromeda Galaxy, is a distance of 2.54×10^7 light-years from Earth. If the lifetime of a human
kupik [55]

Answer:

0.9999986*c

Explanation:

The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.

\Delta t = \Delta t' * \sqrt{1 - (\frac{v}{c})^2}

Where

Δt is the travel time as seen by a passenger

Δt' is the travel time as seen by someone on Earth

v is the speed of the ship

c is the speed of light in vacuum

We can replace the fraction v/c with x

\Delta t = \Delta t' * \sqrt{1 - x^2}

\sqrt{1 - x^2} = \frac{\Delta t}{\Delta t'}

1 - x^2 = (\frac{\Delta t}{\Delta t'})^2

x^2 = 1 - (\frac{\Delta t}{\Delta t'})^2

x = \sqrt{1 - (\frac{\Delta t}{\Delta t'})^2}

x = \sqrt{1 - (\frac{70}{2.54*10^7})^2} = 0.9999986

It would need to travel at 0.9999986*c

5 0
3 years ago
Someone drops a brick on a 2.6 kg cart moving at 28.2 cm/s. After the collision, the dropped brick and cart are moving together
Softa [21]

Answer:

2.087 kg

Explanation:

From the law of conservation of momentum,

Total momentum before collision = total momentum after collision.

MU + mu = V(M+m)............................ Equation 1

Where M = mass of  the cart, m = mass of the brick, U = initial velocity of the cart, u = initial velocity of the brick, V = velocity of both cart and brick after collision.

Note: The initial velocity of the brick is zero Thus mu = 0

making m the subject of the equation,

m =(MU/V)-M ........................................ Equation 2

Given: M = 2.6 kg, U = 28.2 cm/s = 0.283 m/s, V = 15.7 cm/s = 0.157 m/s.

Substituting into equation 2,

m = (2.6×0.283/0.157)-2.6

m = 2.087 kg

Thus the mass of the brick = 2.087 kg

5 0
2 years ago
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