All categories

3 years ago

Where does the BTC pipeline run?

1 answer:

N76 [4]3 years ago

7 0

The pipeline will run 1,100 miles, from the Sangachal terminal near Baku, the capital of Azerbaijan, through Georgia and to the Turkish Mediterranean port of Ceyhan.

You might be interested in

What is the force in N of an object that has a mass of 7 kilograms and acceleration of 6 m/s/s

Marina86 [1]

Newton's 2nd law of motion: Force = (mass) x (acceleration)

If you want to move a 7-kg object with an acceleration of 6 m/s²,
then you will need to push it with (7 x 6) = 42 newtons of force.

You don't mean the force of an object.

4 0

3 years ago

When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion. Which o

Setler [38]

Answer:

Option: D. Gravity is pulling the crash test dummy in the direction the car is moving.

Explanation:

When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion because the gravity is pulling the crash test dummy in the direction the car is moving.

Basically when the car is starting, the person inside is in static position and the car is going to move. So it is putting a force on the person to move on the same speed. But as the person is sitting static hence gravity is pulling him behind from moving. Hence, The dummy appears to be pressed backward.

7 0

3 years ago

I need help with the last question- it’s very simple

77julia77 [94]

You calculated the density correctly.

When you drop anything into a fluid . . .

-- If the object is MORE dense than the fluid, it sinks.

-- If the object is LESS dense than the fluid, it floats.

3 0

4 years ago

A bullet of mass 0.016 kg traveling horizontally at a speed of 280 m/s embeds itself in a block of mass 3 kg that is sitting at

ivanzaharov [21]

(a) 1.49 m/s

The conservation of momentum states that the total initial momentum is equal to the total final momentum:

$p_i = p_f\\m u_b + M u_B = (m+M)v$

where

m = 0.016 kg is the mass of the bullet

$u_b = 280 m/s$ is the initial velocity of the bullet

M = 3 kg is the mass of the block

$u_B = 0$ is the initial velocity of the block

v = ? is the final velocity of the block and the bullet

Solving the equation for v, we find

$v=\frac{m u_b}{m+M}=\frac{(0.016 kg)(280 m/s)}{0.016 kg+3 kg}=1.49 m/s$

(b) Before: 627.2 J, after: 3.3 J

The initial kinetic energy is (it is just the one of the bullet, since the block is at rest):

$K_i = \frac{1}{2}mu_b^2 = \frac{1}{2}(0.016 kg)(280 m/s)^2=627.2 J$

The final kinetic energy is the kinetic energy of the bullet+block system after the collision:

$K_f = \frac{1}{2}(m+M)v^2=\frac{1}{2}(0.016 kg+3 kg)(1.49 m/s)^2=3.3 J$

(c) The Energy Principle isn't valid for an inelastic collision.

In fact, during an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not: this means that part of the kinetic energy of the system is losted in the collision. The principle of conservation of energy, however, is still valid: in fact, the energy has not been simply lost, but it has been converted into other forms of energy (thermal energy).

4 0

4 years ago

What are the characteristics of globular cluster stars?

AlekseyPX

Old age and hundreds of thousands to millions of member stars.

3 0

3 years ago