Answer:
t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]
Explanation:given values
Half life of lipase t_1/2 = 8 min x 60s/min = 480 s
Rate constant for first order reaction
k_d = 0.6932/480 = 1.44 x 10^-3 s-1
Initial fat concentration S_0 = 45 mol/m3 = 45 mmol/L
rate of hydrolysis Vm0 = 0.07 mmol/L/s
Conversion X = 0.80
Final concentration S = S_0(1-X) = 45 (1-0.80) = 9 mol/m3
K_m = 5mmol/L
time take is given by
![t= -\frac{1}{K_d}ln[1-\frac{K_d}{V_m_0}(k_mln\frac{s_0}{s}+(s_0-s))]](https://tex.z-dn.net/?f=t%3D%20-%5Cfrac%7B1%7D%7BK_d%7Dln%5B1-%5Cfrac%7BK_d%7D%7BV_m_0%7D%28k_mln%5Cfrac%7Bs_0%7D%7Bs%7D%2B%28s_0-s%29%29%5D)
all values are given and putting these value we get
t=1642.83 secs
which is equal to
t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]
At a constant volume and
number of moles of the gas the ratio of T and P is equal to some constant.
At another set of condition, the constant is still the same. Calculations are
as follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 473.15 x 1.00 / 293.15
<span>P2 = 1.61 atm</span>
Answer:
50J
Explanation:
Potential energy = mass (kg) * gravitational accelerations (10N on earth) * height
250 g in kg = 0.25
0.25 * 10 * 20 = 50 J
I think the correct answer is C.
i think the best answer for this question is B)