I know what it is but its hard to see
Answer:
The heat gain of the room due to higher efficiency is 2.84 kW.
Explanation:
Given that,
Output power of shaft = 75 hp
Efficiency = 91%
High efficiency = 95.4%
We need to calculate the electric input given to motor
Using formula of efficiency




We need to calculate the electric input
For, heigh efficiency



The reduction of the heat gain of the room due to higher efficiency is

Put the value into the formula


Hence, The heat gain of the room due to higher efficiency is 2.84 kW.
Weight of the barbell W = 200 Ndistance of the joint is r = 40 cm = 0.4 mtorque created by the weight at the joint is τ = F*r = 200 N*0.4 m = 80 N.mat equilibrium condition , Στ = force*distance - 80 N.m = 0 F'*0.4 - 80 N.m = 0 F'*0.4 = 80 force F' = 200 N