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3 years ago

A coiled up wire carrying a current is called what ?

Physics

1 answer:

kvv77 [185]3 years ago

5 0

Answer:

Solenoids

Explanation:

A coil of current-carrying wire is otherwise known as a solenoid; it is often referred to as an electromagnet.

You might be interested in

1)why do we get electric shock while holding a live wire barefooted and not when wearing rubber shoes?

katrin2010 [14]

Electricity is always going to take the path of least resistance to ground. The rubber in your shoes is not a conductor of electricity, therefore you are not completing the circuit and you don't get shocked. Your bare feet, on the other hand ARE conductors of electricity, so when you hold the wire, you complete the circuit and become the path of least resistance to ground... ZAP!

5 0

3 years ago

A very long train is rolling at 4 m/s along a straight track. An observer is standing on the ground very dangerously close to th

hichkok12 [17]

Answer:

A. $\vec{r}=(6\frac{m}{s})t\ \ \hat{i}$

B. t = 50 s

Explanation:

A. The vectorial equation of the person who is getting closer to the other person is:

$\vec{r}=\vec{v}t$

r: position vector

v: speed vector = 6m/s i (if you consider the motion as a horizontal motion)

Then, you replace and obtain:

$\vec{r}=(6\frac{m}{s})t\ \ \hat{i}$

B. The time is:

$t=\frac{d}{v}$

d: distance to the observer = 300m

v: speed of the person on the car = 6.00 m/s

$t=\frac{300m}{6m/s}=50s$

4 0

3 years ago

A diver leaves the end of a 4.0 m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Consider

shutvik [7]

Answer:

4.0 m/s

Explanation:

The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.

Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

$d=v_x t$

where here we have

d = 3.0 m is the horizontal distance covered

vx is the horizontal velocity

t = 1.3 s is the duration of the fall

Solving for vx,

$v_x = \frac{d}{t}=\frac{3.0 m}{1.3 s}=2.3 m/s$

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

$y(t) = h + v_y t - \frac{1}{2}gt^2$

where

h = 4.0 m is the initial height

vy is the initial vertical velocity

We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

$0=h+v_y t - \frac{1}{2}gt^2\\v_y = \frac{0.5gt^2-h}{t}=\frac{0.5(9.8 m/s^2)(1.3 s)^2-4.0 m}{1.3 s}=3.3 m/s$

So now we can find the magnitude of the initial velocity:

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(2.3 m/s)^2+(3.3 m/s)^2}=4.0 m/s$

4 0

3 years ago

PLEASE HELP MEEE!!!

IRINA_888 [86]

Answer:

Option C

Explanation:

Answer C is the correct option. water can be written as H₂O, which means that there are 2 Hydrogen atoms for every oxygen atom, therefore it will occupy more space than oxygen and push more. there is also one more possibility, if the splitting takes place in Hoffman's Voltameter then the Hydrogen will be close to the cathode as hydrogen is positive. Otherwise, option C is correct answer. Hope this Helps you!

4 0

3 years ago

An earthquake in San Francisco produces a wave with a period of 0.80 seconds and a wavelength of 40 m., How long will it take fo

gtnhenbr [62]

Answer:

A) 3.11 Hrs

Explanation:

Wave speed is given by the formula

$Speed = \frac{wavelength}{Time\: period}$