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egoroff_w [7]
4 years ago
9

Mutations in genes encoding cell signaling proteins contribute to many cancers. For example, a chromosomal translocation fuses t

he Bcr gene to the Abl gene, leading to a constitutively active Bcr–Abl kinase and chronic myeloid leukemia (CML). CML is successfully treated with the drug imatinib (trade name Gleevec), which mimics an Abl kinase substrate and thus inhibits kinase activity. What normal cell molecule, and kinase substrate, does Gleevec mimic?
Chemistry
1 answer:
schepotkina [342]4 years ago
6 0

Imatinib is a small molecule kinase inhibitor. The BCR-ABL kinase can phosphorylate a series of downstream substrates, leading to proliferation of mature granulocytes. Bcr-Abl kinase substrate is the tyrosine. The Protein Tyrosine Kinase activity is an important requirement for malignant transformation, and that it cannot be complemented by any downstream effector, though not all interactions of BCR-ABL with other proteins are phosphotyrosine dependent.

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The light reactions of photosynthesis use _____ and produce _____. (activity 10b) nadph ... nadp+ water ... nadph carbon dioxide
mafiozo [28]

During the light reactions of photosynthesis, the energy from the sun is converted into few amounts of ATP and an energy carrier called NADPH. This is associated with the consumption of water and release of oxygen. So from the choices above, the correct answers are:

 

The light reactions of photosynthesis use <u>water</u> and produce <u>nadph</u>.

5 0
3 years ago
What is the heat of vaporization of ethanol, given that ethanol has a normal boiling point of 63.5°C and the vapor pressure of e
Serjik [45]

Explanation:

According to Clausius-Claperyon equation,

       ln (\frac{P_{2}}{P_{1}}) = \frac{-\text{heat of vaporization}}{R} \times [\frac{1}{T_{2}} - \frac{1}{T_{1}}]

The given data is as follows.

         T_{1} = 63.5^{o}C = (63.5 + 273) K

                         = 336.6 K

        T_{2} = 78^{o}C = (78 + 273) K

                         = 351 K

         P_{1} = 1 atm,             P_{2} = ?

Putting the given values into the above equation as follows.    

        ln (\frac{P_{2}}{P_{1}}) = \frac{-\text{heat of vaporization}}{R} \times [\frac{1}{T_{2}} - \frac{1}{T_{1}}]

       ln (\frac{1.75 atm}{1 atm}) = \frac{-\text{heat of vaporization}}{8.314 J/mol K} \times [\frac{1}{351 K} - \frac{1}{336.6 K}]

                      \Delta H = \frac{0.559}{1.466 \times 10^{-4}} J/mol

                                  = 0.38131 \times 10^{4} J/mol

                                  = 3813.1 J/mol

Thus, we can conclude that the heat of vaporization of ethanol is 3813.1 J/mol.

4 0
3 years ago
72 please help me!!!!!!!!!!!!
kicyunya [14]

compounds. is the answer.

4 0
3 years ago
5. How many moles are in 10g of sodium?
garik1379 [7]

Answer: n = m/M = 10 g / 22.99 g/ mol = 0.43 mol

Explanation: M(Na) = 22.99 g/ mol

4 0
3 years ago
Back talk it’s quiet ain’t no back talk
ale4655 [162]

Answer:

?

Explanation:

????????????????????????????????????????????????????????

I hope you find the answer to your question?

7 0
2 years ago
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