<span>(15.0 g) / (150.0 g) x (100 g) = 10.0 g/100 g H2O </span>
The answer to your question would be silicon. I hope this helped!!!
0.000132 g of hydrated sodium borate (Na₂B₄O₇ · 10 H₂O)
Explanation:
First we need to find the number of moles of sodium borate (Na₂B₄O₇) in the solution:
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume (L)
number of moles of Na₂B₄O₇ = 0.1 × 0.5 = 0.05 moles
We know now that we need 0.05 moles of hydrated sodium borate (Na₂B₄O₇ · 10 H₂O) to make the solution.
Now to find the mass of hydrated sodium borate we use the following formula:
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of hydrated sodium borate = 0.05 / 381 = 0.000132 g
Learn more about:
molar concentration
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How many grams of CO are are needed to react with 3.34g of fe203?
Answer:
As there must be twice as many lithium ions as sulphide ions, the 'numbers'
must be different.
It's 4:8. i.e. 4 sulphides around each lithium; and 8 lithiums around each
sulphur.
It's an antifluorite structure.
