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MatroZZZ [7]
3 years ago
8

A tennis ball is thrown horizontally at a speed of 10 m/s from the top of a building 78.4 meters high. how long does it take the

ball to hit the street?
Physics
1 answer:
cupoosta [38]3 years ago
7 0
When it comes to horizontal projectiles, the formula for time is:

t =  \sqrt{ \frac{2dy}{g} }

Where:
dy = vertical distance or height
g = acceleration due to gravity
t = time

Based on the problem, we know that the height at which the tennis ball was thrown is 78.4 m and the acceleration due to gravity is a constant 9.8m/s2. All you need to do is input that into our equation:
t = \sqrt{ \frac{2dy}{g} }
t = \sqrt{ \frac{(2)(78.4m)}{9.8m/s^{2}} }
t = \sqrt{ \frac{156.8m}{9.8m/s^{2}} }
t = \sqrt{16s^{2}}
t = 4s

The time it would take is 4 seconds.

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