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MatroZZZ [7]
3 years ago
8

A tennis ball is thrown horizontally at a speed of 10 m/s from the top of a building 78.4 meters high. how long does it take the

ball to hit the street?
Physics
1 answer:
cupoosta [38]3 years ago
7 0
When it comes to horizontal projectiles, the formula for time is:

t =  \sqrt{ \frac{2dy}{g} }

Where:
dy = vertical distance or height
g = acceleration due to gravity
t = time

Based on the problem, we know that the height at which the tennis ball was thrown is 78.4 m and the acceleration due to gravity is a constant 9.8m/s2. All you need to do is input that into our equation:
t = \sqrt{ \frac{2dy}{g} }
t = \sqrt{ \frac{(2)(78.4m)}{9.8m/s^{2}} }
t = \sqrt{ \frac{156.8m}{9.8m/s^{2}} }
t = \sqrt{16s^{2}}
t = 4s

The time it would take is 4 seconds.

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A 29.0 kg beam is attached to a wall with a hi.nge while its far end is supported by a cable such that the beam is horizontal.
Elanso [62]

The tension in the cable is 169.43 N and the vertical component of the force exerted by the hi.nge on the beam is 114.77 N.

<h3>Tension in the cable</h3>

Apply the principle of moment and calculate the tension in the cable;

Clockwise torque = TL sinθ

Anticlockwise torque = ¹/₂WL

TL sinθ  =  ¹/₂WL

T sinθ  =  ¹/₂W

T = (W)/(2 sinθ)

T = (29 x 9.8)/(2 x sin57)

T = 169.43 N

<h3>Vertical component of the force</h3>

T + F = W

F = W - T

F = (9.8 x 29) - 169.43

F = 114.77 N

Thus, the tension in the cable is 169.43 N and the vertical component of the force exerted by the hi.nge on the beam is 114.77 N.

Learn more about tension here: brainly.com/question/24994188

#SPJ1

6 0
2 years ago
The per-unit impedance of a single-phase electric load is 0.3. The base power is 500 kVA, and the base voltage is 13.8 kV. a. Fi
Leto [7]

Answer:

114.26

Explanation:

a)Formula for per unit impedance for change of base is

Zpu2= Zpu1×(kV1/kV2)²×(kVA2/kVA1)

Zpu2: New per unit impedance

Zpu1: given per unit impedance

kV1: give base voltage

kV2: New bas votlage

kVA1: given bas power

kVA2: new base power

In the question

Zpu2=??

Zpu1= 0.3

kV2=24kV

kV1= 13.8 kV

kVA2= 1MVA ×1000= 1000 kVA

kVA1=500kVA

Zpu2= 0.3(13.8/24)²×(1000/500)

Zpu2= 0.198

b) to find ohmic impedance we will first calculate base value of impedance(Zbase). So,

Zbase= kV²/MVA

  Zbase= 13.8²/(500/1000)

  Zbase=380.88

Now that we have base value of impedance, Zbase, we can calculate actual ohmic value of impedance(Zactual) by using the following formula:

Zpu=Zactual/Zbase

0.3= Zactual/380.88

Zactual= 114.26 ohms

8 0
4 years ago
If a car has a momentum of 2.04 x 104 kgm/s and a velocity of 18 m/s, what is its mass?
muminat

Answer:

Mass = 1133.33 kg (Approx.)

Explanation:

Given:

Momentum = 2.04 x 10⁴ kg[m/s]

Velocity = 18 m/s

Find:

Mass

Computation:

Mass = Momentum / Velocity

Mass = [2.04 x 10⁴] / 18

Mass = 1133.33 kg (Approx.)

5 0
3 years ago
Which of the following choices is an example of an allele?
VikaD [51]

Answer:

Blue eye-color gene

7 0
3 years ago
Part AFind the x- and y-components of the vector d⃗ = (4.0 km , 29 ∘ left of +y-axis).Express your answer using two significant
Hoochie [10]

Solution :

Part A .

Given : The x and y components of the vector, d = \text{4 km 29} degree left of y-axis.

So the x component is = -4 x sin (29°) = -1.939 km

           y component is = 4 x cos (29°) = 3.498 km

Part B

Given : The x and y components of the vector, \text{v = 2 cm/s} , \text{-x direction}

So the x component is = -2 cm/s

           y component is = 0

Part C

Given : The x and y components of the vector, \text{a = 13 m/s, 36 degree} left of y-axis.

So the x component is = -13 x sin (36°) = -7.6412 m/S^2

           y component is = -13 x cos (36°) = -10.517 m/S^2

3 0
3 years ago
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