Answer:
The value of the gas equilibrium constant Kp is 18.3
Explanation:
Step 1: Data given
Kp= Kc(RT)^Δn
Temperature = 298 K
Kc = 18.3
Step 2: The balanced equation
C₄(s) + 4 O₂(g) ⇌ 4 CO₂(g)
Step 3: Calculate Kp
Kp= Kc(RT)^Δn
⇒with Kp = the gas equilibrium constant = TO BE DETERMINED
⇒with Kc = the equilibrium constant = 18.3
⇒R = the gas constant = 0.08206 L* atm/mol*K
⇒T = the temperature = 298 K
⇒Δn = mol gas phase product – mol gas phase reactant = 4-4 =0
Kp = 18.3 * (0.08206*298)^0
Kp = 18.3 * 1
Kp = 18.3
The value of the gas equilibrium constant Kp is 18.3
Answer:
option D
Explanation:
Increasing the temperature increases the yield of ammonia and speeds up the reaction as chemical reaction is affected by temperature.
C + O2 --> CO2
18g C = 18/12.01 = 1.49 moles (Limiting Reagent)
62.3-14.3 = 48g oxygen that reacted
48g O = 3 moles
The answer is "Liquid".
Hope I could help you!
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