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erastova [34]
3 years ago
12

Suppose you saw a waxing gibbous moon. What phase would you expect one week later?

Physics
1 answer:
sattari [20]3 years ago
3 0

The gibbous moon spends roughly a week waxing, from the First Quarter until the Full Moon.  (This is the second week following a New Moon.)

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The energy transformation a leaf on a tree undergoes when sunlight shines on it is an example of what?
Damm [24]

Answer:Radiant to chemical

Explanation:

6 0
3 years ago
In which layer of Earth’s interior does convection occur?
Tresset [83]

<u>Answer: </u>

Earth convection occurs at the mantle layer

<u>Explanation: </u>

The movement of less dense material  above the more dense material  is called as convection.  The mantle is the layer that lies between the core and the crust of the earth. The mantle is composed of rocks containing silicon, magnesium, oxygen,  aluminium, iron and other minerals.

The heat energy of the core is transmitted  to the rock in the lower mantle.  This makes the rock with less temperature that lies  in  upper mantle to move down slowly.  Now the rocks that are pushed up  is eventually cooled and again pushed down by the hotter rock  from the lower mantle. This is called as convection in earth’s mantle .

5 0
3 years ago
Read 2 more answers
A table exerts a force on the ground. The ground exerts
agasfer [191]

Answer:

hey from what I know the answer is C

Explanation:

When a book is kept on a table , weight (gravitational force) of book acts on table vertically downwards and as a reaction of weight , table also exerts an equal and opposite ( upward) force on book .

5 0
3 years ago
Two cars are traveling in the same direction and with the same speed along a straight highway. Does either driver hear a differe
Trava [24]

Answer:

No, either driver can not hear a different frequency from the other car's horn than they would if the cars were stationary.

Explanation:

Either driver hear a different frequency from the other car's horn than they would if the cars were stationary if two cars are traveling in the same direction and with the same speed along a straight highway because neither driver experiences a Doppler shift

8 0
3 years ago
1. Apply a constant force of 50 N directed to the right of the 50 kg Box. (2 pts)
kotegsom [21]

As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.

Then   friction force = 80 Newtons              but in the opposite direction.

Friction force =  Mu  * Normal force exerted by ground  =  Mu * weight of box

So we find Mu.

Mu = coefficient of friction between box and horizontal surface

          = Force of friction / weight  =  80 / 50 * 9.81 = 0.163

When an identical box is placed on top, the force of friction is

      = Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons

7 0
3 years ago
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