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erastova [34]
3 years ago
12

Suppose you saw a waxing gibbous moon. What phase would you expect one week later?

Physics
1 answer:
sattari [20]3 years ago
3 0

The gibbous moon spends roughly a week waxing, from the First Quarter until the Full Moon.  (This is the second week following a New Moon.)

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An airplane flies horizontally with a constant speed of 155.0 m/s at an unknown altitude. A package is released out of the airpl
vladimir1956 [14]

Answer:

 y₀ = 1020.3 m

Explanation:

This is a projectile launching exercise, in this case as the package is released its initial vertical velocity is zero.

            y = y₀ + v_{oy} t - ½ g t²

when it reaches the ground its height is zero

           0 = y₀ + 0 - ½ g t²

           y₀ = ½ g t²

           

let's calculate

         y₀ = ½ 9.8 14.43²

         y₀ = 1020.3 m

8 0
3 years ago
Air enters a nozzle steadily at 2.21 kg/m3 and 20 m/s and leaves at 0.762 kg/m3 and 150 m/s. If the inlet area of the nozzle is
saveliy_v [14]

Answer:

a) The mass flow rate through the nozzle is 0.27 kg/s.

b) The exit area of the nozzle is 23.6 cm².

Explanation:

a) The mass flow rate through the nozzle can be calculated with the following equation:

\dot{m_{i}} = \rho_{i} v_{i}A_{i}

Where:

v_{i}: is the initial velocity = 20 m/s

A_{i}: is the inlet area of the nozzle = 60 cm²  

\rho_{i}: is the density of entrance = 2.21 kg/m³

\dot{m} = \rho_{i} v_{i}A_{i} = 2.21 \frac{kg}{m^{3}}*20 \frac{m}{s}*60 cm^{2}*\frac{1 m^{2}}{(100 cm)^{2}} = 0.27 kg/s  

Hence, the mass flow rate through the nozzle is 0.27 kg/s.

b) The exit area of the nozzle can be found with the Continuity equation:

\rho_{i} v_{i}A_{i} = \rho_{f} v_{f}A_{f}

0.27 kg/s = 0.762 kg/m^{3}*150 m/s*A_{f}

A_{f} = \frac{0.27 kg/s}{0.762 kg/m^{3}*150 m/s} = 0.00236 m^{2}*\frac{(100 cm)^{2}}{1 m^{2}} = 23.6 cm^{2}

Therefore, the exit area of the nozzle is 23.6 cm².

I hope it helps you!                                                                  

5 0
3 years ago
Read 2 more answers
Which of these materials is an example of an insulator?
geniusboy [140]
Rubber. The other three are metals, and therefore good conductors.
7 0
3 years ago
light inside the thin glass tube of a laparoscopic surgical device strikes the edge of the glass tube and is entirely reflected
vovangra [49]

Light striking the walls of the glass cylinder and reflecting in inside tube itself is a phenomenon known as total internal reflection.

<h3>What word best describes reflection, in your opinion?</h3>

Reflection is often synonymous with the verbs cogitate, contemplate, reason, hypothesize, and think. All of these expressions mean "using one's intellect, judgment, or inference faculties," but the word "reflect" means carefully considering a recollection.

<h3>What does it mean to give reflection some thought?</h3>

constant verb When you ruminate, you seriously consider something. Alternatives include thinking, analyzing, planning, and thinking. More phrases containing "reflect" Reflecting feelings is the act of observing a person's verbal and nonverbal signs for their emotions and feelings, then immediately communicating (or reflecting) those attitudes to the user or customer.

To know more about reflection visit:

brainly.com/question/8714151

#SPJ4

8 0
1 year ago
An object is thrown directly upwards from the ground at a velocity of 9ms. Recalling that the acceleration due to gravity is −gm
olga55 [171]

Answer:

Explanation:

Given

Object is thrown with a velocity of u=9\ m/s

Acceleration due to gravity is -g (i.e. acting downward)

Vertical distance traveled by object is given by

v^2-u^2=2as  

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

at maximum height final velocity is zero

0-(9)^2=2\times (-g)\times (s)

s=\frac{81}{2g}=\frac{40.5}{g}\ m

time taken to reach maximum height

using

v=u+at

0=9-gt

t=\frac{9}{g}\ s

6 0
3 years ago
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