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erastova [34]
3 years ago
12

Suppose you saw a waxing gibbous moon. What phase would you expect one week later?

Physics
1 answer:
sattari [20]3 years ago
3 0

The gibbous moon spends roughly a week waxing, from the First Quarter until the Full Moon.  (This is the second week following a New Moon.)

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How is ultraviolet light and infrared light alike? How are they different?
swat32
Alike - both part of the light spectrum, cannot be seen with the naked eye

Different - IR is less energetic than UV, UV has a shorter wavelength than IR

IR - infrared
UV - ultraviolet
5 0
3 years ago
A student notices that an inflated balloon gets larger when it is warmed by a lamp. Which best describes the mass of the balloon
nirvana33 [79]
It gets larger because
well let me give you an example
so today in class we looked at a lava lamp with wax inside and there was a lightbulb at the bottom.
we watched as the wax floated up because the molecules inside the wax spreads out and makes the wax less dense.
the wax floats up because (which is related to the balloon getting bigger) the wax is getting less dense and the particles get bigger which ALSO makes the wax less dense.
hope this helps and hope you can relate it to your problem! say thanks if I did help AT ALL! :)
7 0
3 years ago
Read 2 more answers
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VMariaS [17]

Answer:

a.proton, proton

hope this helped :) have a goodday

6 0
3 years ago
Help me pls 13 points
mezya [45]

Answer:

wave frequency

Explanation:

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7 0
2 years ago
Two cars are traveling along a straight road. Car A maintains a constant speed of 95 km/h and car B maintains a constant speed o
natulia [17]

Answer

given,

Speed of car A = 95 Km/h

                         = 95 x 0.278 = 26.41 m/s

Speed of Car B = 121 Km/h

                         = 121 x 0.278 = 33.64 m/s

Distance between Car A and B at t=0 = 41 Km

a) Distance travel by car B

   d = 26.41 t + 41000

speed of the car A = 33.64 m/s

distance = s x t

26.41 t + 41000 = 33.64 x t

7.23 t = 41000

t = 5670.82 s

time taken by Car B to cross Car A is equal to t = 5670.82 s

distance traveled by car A

D = s x t  = 26.41 x 5670.82 = 149766.25 m = 149.76 Km

b) distance travel by the car B in 30 s after overtaking car A

   D' = s x t = 33.64 x 30 = 1009.2 m = 1 Km  

8 0
2 years ago
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