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Alenkinab [10]
3 years ago
5

A car and a large truck traveling at the same speed collide head-on and stick together. Which vehicle experiences the larger cha

nge in the magnitude of its momentum
Physics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

Both vehicles experience the same change in momentum

Explanation:

Let m represent the mass of the vehicle, and 2m represent the mass of the large truck, and let v represent their initial speed, we have;

The total initial momentum, p_i given as follows;

p_i = 2·m·v - m·v = m·v

The total final momentum, p_f = (2·m + m) × v_f

By the principle of conservation of linear momentum, the total initial momentum = The total final momentum

m·v = (2·m + m) × v_f

m·v = 3·m·v_f

∴ v = 3 × v_f

v_f = v/3

The change in the momentum for the large truck = 2·m·v - 2·m·v_f

Therefore;

The change in the momentum for the large truck = 2·m·v - 2·m·v/3 = 2·m·(v - v/3)

The change in the momentum for the large truck = 2·m·(v - v/3) = 2·m·2·v/3 =  4·m·v/3

The change in the momentum for the car = m·v - m·(-v_f) = m·v - m·(-v)/3 = m·v + m·(v)/3 = 4·m·v/3

Therefore, the change in the momentum for the large truck = The change in the momentum for the car and both vehicles experience the same change in momentum.

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Mariulka [41]

Answer: 0.4 Amps

Explanation:

Voltage of battery = 24 Volts

Current I = ?

Resistance of searchlight (R)= 60ohms (Ω is the symbol for ohms)

Then, apply the formula for ohms law

Voltage = Current x resistance

i.e V = I x R

24V = I x 60Ω

I = 24V / 60Ω

I = 0.4 Amps (Amps is the unit of current)

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3 0
3 years ago
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Lubov Fominskaja [6]
This is hard sorry but I need to anwser
7 0
3 years ago
Read 2 more answers
Can someone please help
ki77a [65]

Answer:

Acceleration of that planet is 30 \frac{m}{s^{2} }.

Given:

initial speed of hammer = 0 \frac{m}{s}

time = 1 s

distance = 15 m

To find:

Acceleration due to gravity = ?

Formula used:

Distance covered by hammer is given by,

s = ut + \frac{1}{2} a t^{2}

s = distance

u = initial speed of hammer

t = time taken by hammer to reach ground

a = acceleration

Solution:

Distance covered by hammer is given by,

s = ut + \frac{1}{2} a t^{2}

s = distance

u = initial speed of hammer

t = time taken by hammer to reach ground

a = acceleration

u = 0

t = 1 s

s = 15 m

a = g

Thus substituting these value in above equation.

15 = 0 + \frac{1}{2} g 1^{2}

g = 15 × 2

g = 30 \frac{m}{s^{2} }

Thus, acceleration of that planet is 30 \frac{m}{s^{2} }.

8 0
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Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:

2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

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salantis [7]

Explanation:

Below is an attachment containing the solution.

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