We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.
The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.
Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, 
moles = 0.375 moles of nitrogen is required.
Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.
Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.
Answer:
B, (logic) D (knowledge)
Explanation:
Problem solving refers to the ability to figure out an answer to a question. The question can be general, such as how to design an experiment, or it can be more specific, such as how to calculate speed (its distance divided by time). Reasoning is closely related to problem solving. When scientists reason, they use logic and knowledge to make conclusions and decisions. The processes of reasoning and problem solving are usually more educational than the answer. Figuring something out is a wonderful workout for your brain.
(got this from the source)
Hope this helps!!!
Hi!
Electrons are particles which basically 'orbit' around the nucleus. Protons and neutrons are condensed, in a fixed position inside the nucleus.
With this in mind, the answer will be C.
Hopefully, this helps! =)
Answer:
5.0 38 84.0 749.7 528.0 729.0 738.9 739.0
The average atomic mass of the element is the sum of the products of the percentage abundance of isotope and its mass number. Therefore, for atomic mass equal to 58.933, the most abundant isotope is cobalt-59. Thus, the answer is letter C.
