Answer:
5
Explanation:
Given parameters:
Hydrogen ion concentration = 0.00001M
Unknown:
pH of the solution =?
Solution:
The pH is used to estimate the degree of acidity or alkalinity of a solution. To solve for pH of any solution, we use the expression below;
pH = -log [H⁺]
[H⁺] is the hydrogen ion concentration
pH = -log (1 x 10⁻⁵)
pH = -(-5) = 5
Answer:
Water has a very high heat capacity, which makes it useful for radiators ... the temperature change that a given substance will undergo when it is either heated or cooled. ... The heat that is either absorbed or released is measured in joules. ... A 15.0 g piece of cadmium metal absorbs 134 J of heat while rising from 24.0°C to ...
Answer:
The volume is 13, 69 L
Explanation:
We use the formula PV=nRT. We convert the temperature in Celsius into Kelvin and the pressure in mmHg into atm.
0°C= 273K---> 56°C= 56 + 273= 329K
760 mmHg----1 atm
719 mmHg----x= (719 mmHgx 1 atm)/760 mmHg= 0,95 atm
PV=nRT ---> V= (nRT)/P
V=( 0,482 molx 0,082 l atm/K mol x 329K)/0,95 atm
<em>V=13,68778526 L</em>
Assuming that the reaction from A and C to AC5 is only
one-step (or an elementary reaction) with a balanced chemical reaction of:
<span>A + 5 C ---> AC5 </span>
Therefore the formation constant can be easily calculated
using the following formula for formation constant:
Kf = product of products concentrations / product of reactants
concentration
<span>Kf = [AC5] / [A] [C]^5 </span>
---> Any coefficient from the balanced chemical
reaction becomes a power in the formula
Substituting the given values into the equation:
Kf = 0.100 M / (0.100 M) (0.0110 M)^5
Kf = 6,209,213,231
or in simpler terms
<span>Kf = 6.21 * 10^9 (ANSWER)</span>
Answer:
See explanation
Explanation:
For a reaction that proceeds by E1 mechanism, the rate determining step involves the formation of the carbocation.
The rate of formation of this carbocation depends only on the concentration of the t-butyl bromide since it is the only specie that enters into the rate equation.
Hence, when the concentration of t-butyl bromide is tripled, the rate of reaction is tripled.
Methanol does not enter into the rate equation hence doubling its concentration does not affect the rate of reaction.
