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Basile [38]
3 years ago
8

A remote controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by v= [5.00 m/

s – (0.0180 m/s3)t^2 ]i+[2.00 m/s + (0.550 m/s2)t ]j .
a) What are ax(t) and ay(t), the x- and y- components of cars acceleration as a function of time?
b) What are the magnitude and direction of the velocity of the car at t= 8 sec?
c) What is the magnitude and direction of cars acceleration at t=8 sec
Physics
1 answer:
Volgvan3 years ago
5 0
Maybe try A for your answer
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A mass of 25.5 g of H2O(g) at 373 K is mixed with 325 g of H2O(l) at 285 K and 1 atm. Calculate the final temperature of the sys
Vedmedyk [2.9K]

Answer:

331.28 K

Explanation:

To solve this problem, you need to know that the heat that the water at 373 K is equal to the heat that the water at 285 K gains.

First, we will asume that at the end of this process there won't be any water left in gaseous state.

The heat that the steam (H20(g)) loses is equal to the heat lost because the change of phase plus the heat lost because of the decrease in temperature:

Q_g = c_l*m_{wg} + m_{wg}*c*(T_{og}-T{fg})

The specific Heat c of water at 298K is 4.18 kJ/K*kg.

The latent heat cl of water is equal to  2257 kJ/kg.

The heat that the cold water gains is equal to heat necessary to increase its temperature to its final value:

Q_l = m_{wl}*c*(T_{fl}-T_{ol})

Remember that in equilibrium, the final temperature of both bodies of water will be equal.

Then:

Q_g = Q_l\\c_l*m_{wg} + m_{wg}*c*(T_{og}-T{fg}) = m_{wl}*c*(T_{fl}-T_{ol})\\2257 kJ/kg*0.0255 kg + 0.0255 kg*4.18 kJ/kg*K*(373K - T_f) = 0.325 kg*4.18kJ/kg*K*(T_f-285K)\\57.5535 kJ + 39.75807kJ - 0.10659T_f = 1.3585 T_f - 387.1725 kJ\\484.48407 kJ = 1.46244 T_f\\T_f = 484.48407 kJ /1.46244 = 331.28 K

4 0
3 years ago
Which configuration would produce an electric current? A) Rotate a coil of copper wire between two magnets. B) Connect a wire be
FrozenT [24]

the answer is (A) the movement of the magnet relative to the coil

4 0
3 years ago
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A compact car, mass 660 kg, is moving at 1.00 ✕ 102 km/h toward the east. The driver of the compact car suddenly applies the bra
Maslowich

Answer:59.43\times 10^3 kg-m/s

Explanation:

Given

mass of car m=660 kg

Initial velocity of car =102 km/h\approx 28.33 m/s towards east

Time taken to stop t=2.1 s

Force exerted F_{avg}=4.8\times 10^3 N

change in momentum is given  by impulse imparted to the car

Impulse(J)=-F\cdot t

J=-4.8\times 10^3\times 2.1

J=-59.49\times 10^3 kg-m/s

negative Sign indicates that impulse is imparted opposite to the direction of motion

magnitude of momentum J=59.49\times 10^3

6 0
3 years ago
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How does the color of water affect its evaporation rate
olga_2 [115]
Well my thinking is that the lighter the slower the water evaporates or the darker the faster becuase dark colors absorb light and allows a lot of heat to be generated or not at all.

8 0
3 years ago
collision occurs betweena 2 kg particle traveling with velocity and a 4 kg particle traveling with velocity. what is the magnitu
anzhelika [568]

Answer:

metre per seconds

Explanation:

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