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SSSSS [86.1K]
3 years ago
6

A cup has a mixture of iron filings, sand, and salt. How could you separate theses 3 materials? Write out the procedures you wou

ld follow and what materials you would need to complete the task.
Chemistry
1 answer:
Anarel [89]3 years ago
3 0

Explanation:

A cup of mixtures of iron fillings, sand and salt is a mixture who constituents are in the same phase i.e solid.

To separate them out we use the physical properties of the substances.

  • First spread out the mixture uniformly over a piece of paper or on the table.
  • Pass a bar magnet over it.
  • The iron fillings will become attracted to the magnet and separate from the mixture.
  • then pour water into the mixture of sand and salt
  • the salt will dissolve since sand is made up of quartz which are highly insoluble.
  • separate the water solution. Evaporate to dryness and recover the salt.
  • the sand is left behind and dried.

learn more:

Mixtures brainly.com/question/1832352

#learnwithBrainly

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Given a 1.50 Liters of solution that contains 62.5 grams of magnesium oxide. What is the Molarity of that solution?
eimsori [14]
RMM of magnesium oxide=24+16=40
40g=1mol
therefore 62.5g will have =62.5/40=1.5625 moles
1.5 litres contain 1.5625 mols
therefore 1 litre =1*1.5625/1.5=1.042M
5 0
4 years ago
Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in and the atom emits a photon of lig
Usimov [2.4K]

Complete Question

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n=4 and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices

Answer:

n=2

Explanation:

From the question we are told that:

Wavelength \lambda=486nm=>486*10^{-9}

Generally the equation for Atom Transition is mathematically given by

\frac{1}{\lambda}=R_{\infty }(\frac{1}{n_1^2}-\frac{1}{n_2^2})

Where

Rydberg constant R_{\infty}=1.097*10^7

Therefore

\frac{1}{486*10^{-9}}=1.097*10^7*(\frac{1}{n_1^2}-\frac{1}{4^2})

(\frac{1}{n_1^2}-\frac{1}{4^2})=\frac{1}{486*10^{-9}*1.097*10^7}

n_1^2=3.98

n=1.99

n=2

6 0
3 years ago
A gas occupies 3.8 L at -18° C and 975. torr. What volume would this gas occupy at STP?
Aleks04 [339]

To solve the question we will assume that the gas behaves like an ideal gas, that is to say, that there is no interaction between the molecules. Assuming ideal gas we can apply the following equation:

PV=nRT

Where,

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is a constant

T is the temperature

Now, we have two states, an initial state, and a final state. The conditions for each state will be.

Initial state (1)

P1=975Torr=1.28atm

V1=3.8L

T1=-18°C=255.15K

Final state(2), STP conditions

P2=1atm

T2=273.15K

V2=?

We will assume that the number of moles remains constant, so the nR term of the first equation will be constant. For each state, we will have:

\begin{gathered} \frac{P_1V_1}{T_1}=nR \\ \frac{P_2V_2}{T_2}=nR \end{gathered}

Since nR is the same for both states, we can equate the equations and solve for V2:

\begin{gathered} \frac{P_{2}V_{2}}{T_{2}}=\frac{P_1V_1}{T_1} \\ V_2=\frac{P_{1}V_{1}}{T_{1}}\times\frac{T_2}{P_2} \end{gathered}

We replace the known values:

V_2=\frac{1.28atm\times3.8L}{255.15K}\times\frac{273.15K}{1atm}=5.2L

At STP conditions the gas would occupy 5.2L. First option

8 0
1 year ago
WHICH ONE?????????????????? Brainlest
FromTheMoon [43]

Answer:

I believe it would be C, The number of atoms in the reactants is equal to the number of atoms composing the products

Explanation:

hope this helps! :D

have a miraculous day!! <3

5 0
2 years ago
Read 2 more answers
Choose the element that IS NOT in the same period as Potassium.
Lesechka [4]
E. sodium is the answer

8 0
4 years ago
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