The measure of both the interior angles are 70 and 110 degree.
<h3>What are Parallel Lines ?</h3>
Lines they never intersect with each other and the distance between them always remains same are called parallel lines.
It is given that
Line l and m are parallel lines and are intersected by a transversal ,n
Interior angles of the same side are (2x−8) degree and (3x−7) degree
Applying the property of interior angles of parallel lines
2x -8 + 3x - 7 = 180 degree
5x -15 = 180
5x = 195
x = 39 degree
Both the angles have measure of
2 * 39 - 8 = 70 degree
3 * 39 -7 = 110 degree
Therefore the measure of both the angles are 70 and 110 degree.
The complete question is
Two parallel lines l and m are cut by a transversal n . If the interior angles of the same side of n are (2x−8) degree and (3x−7) degree , find the measure of each of these angles.
To know more about Parallel Lines
brainly.com/question/16701300
#SPJ1
<u>Given</u>:
Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.
The marbles are selected by not replacing the drawn ones.
We need to the probability of selected a black marble and then a white marble without replacement.
<u>Probability</u>:
Let B denote the black marble.
Let W denote the white marble.
The probability of selecting a black marble is 
The probability of selecting a white marble without replacement is 
The probability of selecting a black marble and then a white marble without replacement is given by
Substituting the values, we get;
Thus, the probability of selecting a black marble and then a white marble without replacement is 
Answer:
Step-by-step explanation:
Using the rule of exponents
= 
, hence
f(- 2) = 
= 
=
Answer:
It would take 19 hours and 36 minutes until there are 1040 bacteria present.
Step-by-step explanation:
Given that in a lab experiment, 610 bacteria are placed in a petri dish, and the conditions are such that the number of bacteria is able to double every 23 hours, to determine how long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present, the following calculation must be performed:
610X = 1040
X = 1040/610
X = 1.7049
2 = 23
1.7049 = X
1.7049 x 23/2 = X
39.2131 / 2 = X
19.6 = X
100 = 60
60 = X
60 x 60/100 = X
36 = X
Therefore, it would take 19 hours and 36 minutes until there are 1040 bacteria present.
