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VikaD [51]
4 years ago
14

What is the approximate solution of e2x−3 = 7?

Mathematics
2 answers:
evablogger [386]4 years ago
8 0
E2x-3=7  (multiply by ln e on both sides)
ln e of e=1
>>> 2x-3=ln 7
         x=(ln 7 + 3)/2
         x=2.47   (to 3 s.f)
Harlamova29_29 [7]4 years ago
3 0

The approximate solution is .69314718

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In trapiziod ABCD with bases AB and DC , diagonals intersect at point O. Find the length of diagonal BD, if BO=6 cm and A/O=3/1
ElenaW [278]

Answer:

the length of the diagonal BD is 8 cm

Step-by-step explanation:

The computation of the length of diagonal BD is as follows

Here the trapezoid diagonals divides each other in an equivalent ratio

So, equation would be

AO ÷ OC = OB ÷ OD

Now put there values to the above equation

3 ÷ 1 = 6 ÷ OD

3OD = 6

Now divided it by 3 in both the sides

OD = 2

Now the BD would be

= BO + OD

= 6 +  2

= 8 cm

hence, the length of the diagonal BD is 8 cm

3 0
3 years ago
What is the slope in the standard form equation 3x + 2y = 10
Annette [7]
M=3/2 pls mark brainliest
7 0
3 years ago
1. Graph the function g(x) = [X1 + 4 as a translation of the
Elenna [48]

Answer:

The translation did not effect the domain

The translation effected the range

Step-by-step explanation:

The given graph represents f(x) = IxI

The domain of f(x) is {x : x ∈ R}, where R is the set of real numbers

The range of f(x) is {y : y ≥ 0}

The graph of g(x) is attached down

g(x) = IxI + 4

The domain of g(x) is {x : x ∈ R}, where R is the set of real numbers

The range of g(x) is {y : y ≥ 4}

The graph of g(x) is the image of the graph of f(x) after translate it 4 units up

∵ The translation is vertically

∴ The domain of f(x) = the domain of g(x)

∵ The domain of f(x) is {x : x ∈ R}

∴ The domain of g(x) is {x : x ∈ R}

∴ The translation did not effect the domain

∵ g(x) = f(x) + 4

∵ The range of f(x) is {y : y ≥ 0}

- Add 4 to the value 0

∴ The range of g(x) is {y : y ≥ 0 + 4}

∴ The range of g(x) is {y : y ≥ 4}

∴ The range of g(x) not equal the range of f(x)

∴ The translation effected the range

5 0
3 years ago
The perimeter of Raul's picture frame is 108 centimeters. The length of the picture frame is 18 centimeters. What is the width o
o-na [289]
Perimeter of a rectangle= 2(length)+2(width)

Data:
Perimeter=108 cm
length=18 cm

therefore:
108 cm=2(18 cm)+2(width)
108 cm=36 cm+2 (width)
2 width=108 cm -36 cm=
2 width=72 cm
width=72cm/2
width=36 cm

Answer: the width of the picture frame would be 36 cm.
7 0
4 years ago
Can someone help with this?? :)))
Y_Kistochka [10]

Answer:

5.3

You split them up into smaller root numbers and add them together

6 0
2 years ago
Read 2 more answers
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