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VikaD [51]
3 years ago
14

What is the approximate solution of e2x−3 = 7?

Mathematics
2 answers:
evablogger [386]3 years ago
8 0
E2x-3=7  (multiply by ln e on both sides)
ln e of e=1
>>> 2x-3=ln 7
         x=(ln 7 + 3)/2
         x=2.47   (to 3 s.f)
Harlamova29_29 [7]3 years ago
3 0

The approximate solution is .69314718

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