3 years ago

What is the approximate solution of e2x−3 = 7?

Mathematics

2 answers:

evablogger [386]3 years ago

8 0

E2x-3=7 (multiply by ln e on both sides)
ln e of e=1
>>> 2x-3=ln 7
x=(ln 7 + 3)/2
x=2.47 (to 3 s.f)

Harlamova29_29 [7]3 years ago

3 0

The approximate solution is .69314718

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