Answer:
sulcus
Explanation:
A sulcus is an indentation or depression in the brain that causes it to look like it ridges or folds
Cerebral sulci and fissures are grooves between the adjacent gyri on the surface of the cerebral hemispheres.
Sulci can be basically can be divided into three basic function
limiting sulcus: This happens to develop between areas differing in structure and function, for example central sulcus
axial sulcus: This develops along the axis of a rapidly growing/developing area (e.g. calcarine sulcus)
operculated sulcus: a sulcus may be between two structurally-different areas and a third sulcus may lie in its wall and does not appear on the surface (e.g. lunate sulcus)
Answer:
1.19 m/s²
Explanation:
The frequency of the wave generated in the string in the first experiment is f = n/2l√T/μ were T = tension in string = mg were m = 1.30 kg weight = 1300 g , μ = mass per unit length of string = 1.01 g/m. l = length of string to pulley = l₀/2 were l₀ = lent of string. Since f is the second harmonic, n = 2, so
f = 2/2(l₀/2)√mg/μ = 2(√mg/μ)/l₀ (1)
Also, for the second experiment, the period of the wave in the string is T = 2π√l₀/g. From (1) l₀ = 2(√mg/μ)/f and from (2) l₀ = T²g/4π²
Equating (1) and (2) we ave
2(√mg/μ)/f = T²g/4π²
Making g subject of the formula
g = 2π√(2√(m/μ)/f)/T
The period T = 316 s/100 = 3.16 s
Substituting the other values into , we have
g = 2π√(2√(1300 g/1.01 g/m)/200 Hz)/3.16
g = 2π√(2 × 35.877/200 Hz)/3.16
g = 2π√(71.753/200 Hz)/3.16
g = 2π√(0.358)/3.16
g = 2π × 0.599/3.16
g = 1.19 m/s²
Explanation:
It is given that,
Wavelength of x-rays = 2 nm
Plane spacing, d = 0.281 nm
It is assumed to find the scattering angle for second order maxima.
For 2nd order, Bragg's law is given by :

For second order, n = 2

Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.
Answer:
The mass of air in the box is 0.78 grams.
Explanation:
A litre equals a cubic decimetre. By definition of density (
), in grams per litre, we calculate the mass of air inside the cube (
), in grams:
(1)
Where
is the volume occupied by air within the cube, in litres.
If we know that
and
, then the mass of air is:


The mass of air in the box is 0.78 grams.
Answer:
The horizontal force is 106.89 N.
Explanation:
Given that,
Work done = 310 J
Distance = 2.9 m
We need to calculate the horizontal force
Using formula of work done

Where, 

Put the value into the formula



Hence, The horizontal force is 106.89 N.