Moles He = 7.83 x 10^24 / 6.02 x 10^23 =13.0
<span>mass He = 13.0 mol x 4.00 g/mol = 52.0 g</span>
<span>A piece of lithium is placed on the surface of some water in a beaker. Hydrogen is given off and Lithium hydroxide is formed. The word equation would be as follows:
</span>
lithium<span> + </span>water<span>→ </span>lithium hydroxide<span> + </span>hydrogen
Hope this answers the question. Have a nice day.
Here we have to get the
of the reaction at 520 K temperature.
The
of the reaction is 1.705 atm
We know the relation between
and
is
, where
= The equilibrium constant of the reaction in terms of partial pressure,
= The equilibrium constant of the reaction in terms of concentration and N = number of moles of gaseous products - Number of moles of gaseous reactants.
Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅
Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole
The given value of
is 4.0×10⁻²
The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.
On plugging the values in the equation we get,

Or,
= 1.705 atm
Thus, the
of the reaction is 1.705 atm
Answer:
c = 0.0432moldm ^−3
Explanation:
The first step would be to find the molar ratio in the reaction. Now generally, one can simplify strong acid-strong base reaction by saying:
Acid+Base ->Salt+ Water