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Mariana [72]
3 years ago
10

What is the solubility of NH4Cl at 50°C?

Chemistry
2 answers:
astra-53 [7]3 years ago
8 0

The correct answer is E. 50 grams

The solubility of Ammonium Chloride has an increasing trend as the temperature increases. Experiments show that the solubility at 323K is approximately 50.4 grams per 100 grams o water thus this value is close to choice D, 50 grams

maw [93]3 years ago
3 0

<u>Answer:</u> The correct answer is Option E.

<u>Explanation:</u>

Solubility is defined as the amount of substance (known as solute) which is dissolved in a unit volume of liquid substance (known as solvent) to produce a saturated solution at specific temperature and pressure. It is expressed in number of moles of solute present per 100 grams of solvent.

This property is directly dependent on temperature. As, the temperature increases, the solubility of the solute increases and vice-versa.

\text{Solubility}\propto \text{Temperature}

NH_4Cl is an ionic salt whose solubility increases as we increase the temperature.

The solubility of ammonium chloride at 50°C is 50 grams.

Hence, the correct answer is Option E.

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A sample of CaCO3(s) is introduced into a sealed container of volume 0.638 L and heated to 1000 K until equilibrium is reached.
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Answer:

the mass of CaO present at equilibrium is, 0.01652g

Explanation:

K_p = [CO_2] = 3.8×10⁻²

Now we have to calculate the moles of CO₂

Using ideal gas equation,

PV =nRT

P = pressure of gas = 3.8×10⁻²

T = temperature of gas = 1000 K

V = volume of gas = 0.638 L

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mole.k

\frac{3.8 * 10^2 * 0.638}{0.0821 * 1000} \\= 2.95 * 10^-^4

Now we have to calculate the mass of CaO

mass = 2.95 * 10 ⁻⁴ × 56

= 0.01652g

Therefore,

the mass of CaO present at equilibrium is, 0.01652g

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