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3 years ago

What is the solubility of NH4Cl at 50°C?

Chemistry

2 answers:

astra-53 [7]3 years ago

8 0

The correct answer is E. 50 grams

The solubility of Ammonium Chloride has an increasing trend as the temperature increases. Experiments show that the solubility at 323K is approximately 50.4 grams per 100 grams o water thus this value is close to choice D, 50 grams

maw [93]3 years ago

3 0

Answer: The correct answer is Option E.

Explanation:

Solubility is defined as the amount of substance (known as solute) which is dissolved in a unit volume of liquid substance (known as solvent) to produce a saturated solution at specific temperature and pressure. It is expressed in number of moles of solute present per 100 grams of solvent.

This property is directly dependent on temperature. As, the temperature increases, the solubility of the solute increases and vice-versa.

$\text{Solubility}\propto \text{Temperature}$

$NH_4Cl$ is an ionic salt whose solubility increases as we increase the temperature.

The solubility of ammonium chloride at 50°C is 50 grams.

Hence, the correct answer is Option E.

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3 years ago

in example 5.11 of the text the molar volume of n2 at STP is given as 22.42 L/mol how is this number calculatd how does the mola

Valentin [98]

Answer:

V = 22.42 L/mol

N₂ and H₂ Same molar Volume at STP

Explanation:

Data Given:

molar volume of N₂ at STP = 22.42 L/mol

Calculation of molar volume of N₂ at STP = ?

Comparison of molar volume of H₂ and N₂ = ?

Solution:

Molar Volume of Gas:

The volume occupied by 1 mole of any gas at standard temperature and pressure and it is always equal to 22.42 L/ mol

Molar volume can be calculated by using ideal gas formula

PV = nRT

Rearrange the equation for Volume

V = nRT / P . . . . . . . . . (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

Standard values

P = 1 atm

T = 273 K

n = 1 mole

R = 0.08206 L.atm / mol. K

Now put the value in formula (1) to calculate volume for 1 mole of N₂

V = 1 x 273 K x 0.08206 L.atm / mol. K / 1 atm

V = 22.42 L/mol

Now if we look for the above calculation it will be the same for H₂ or any gas. so if we compare the molar volume of 1 mole N₂ and H₂ it will be the same at STP.

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Scandium
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Manganese
Iron
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Copper
Zinc
Yttrium
Zirconium
Niobium
Molybdenum
Technetium
Ruthenium
Rhodium
Palladium
Silver
Cadmium
Lanthanum
Hafnium
Tantalum
Tungsten
Rhenium
Osmium
Iridium
Platinum
Gold
Mercury
Actinium
Rutherfordium
Dubnium
Seaborgium
Bohrium
Hassium
Meitnerium
Darmstadtium
Roentgenium
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