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3 years ago

What is the solubility of NH4Cl at 50°C?

Chemistry

2 answers:

astra-53 [7]3 years ago

8 0

The correct answer is E. 50 grams

The solubility of Ammonium Chloride has an increasing trend as the temperature increases. Experiments show that the solubility at 323K is approximately 50.4 grams per 100 grams o water thus this value is close to choice D, 50 grams

maw [93]3 years ago

3 0

<u>Answer:</u> The correct answer is Option E.

<u>Explanation:</u>

Solubility is defined as the amount of substance (known as solute) which is dissolved in a unit volume of liquid substance (known as solvent) to produce a saturated solution at specific temperature and pressure. It is expressed in number of moles of solute present per 100 grams of solvent.

This property is directly dependent on temperature. As, the temperature increases, the solubility of the solute increases and vice-versa.

$\text{Solubility}\propto \text{Temperature}$

$NH_4Cl$ is an ionic salt whose solubility increases as we increase the temperature.

The solubility of ammonium chloride at 50°C is 50 grams.

Hence, the correct answer is Option E.

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3 years ago

The density of lead is 11.3g/cm^3 and the density of chromium is 7.14g/cm^3. If we have one gram of each metal, what is the rati

Lady bird [3.3K]

The ratio of the volume of lead to the volume of chromium is 22 : 35

Density is simply defined as the mass of a substance per unit volume of the substance.

<h3>Density = mass / volume </h3>

To solve the question given above, we'll begin by calculating the volume of lead and chromium. This can be obtained as follow:

Mass of lead = 1 g

Density of lead = 11.3 g/cm³

<h3>Volume of lead =? </h3>

Density = mass /volume

11.3 = 1 / Volume

Cross multiply

11.3 × Volume = 1

Divide both side by 11.3

Volume = 1 / 11.3

<h3>Volume of lead = 0.088 cm³</h3>

<h3>For Chromium:</h3>

Mass of chromium = 1 g

Density of chromium = 7.14 g/cm³

<h3>Volume of chromium =? </h3>

Density = mass /volume

7.14 = 1 / Volume

Cross multiply

7.14 × Volume = 1

Divide both side by 7.14

Volume = 1 / 7.14

<h3>Volume of chromium = 0.14 cm³</h3>

Finally, we shall determine the ratio of the volume of lead to the volume chromium. This can be obtained as follow:

Volume of lead = 0.088 cm³

Volume of chromium = 0.14 cm³

<h3>Ratio of the volume of lead to chromium =? </h3>

Ratio = Volume of lead / Volume of chromium

Ratio = 0.088 / 0.14

Ratio = 22 / 35

<h3>Ratio = 22 : 35</h3>

Therefore, the ratio of the volume of lead to the volume chromium is 22 : 35

Learn more: brainly.com/question/17262276

5 0

3 years ago

What is the pH of a 0.28 M solution of ascorbic acid

Nady [450]

Hey there!

Values Ka1 and Ka2 :

Ka1 => 8.0*10⁻⁵

Ka2 => 1.6*10⁻¹²

H2A + H2O -------> H3O⁺ + HA⁻

Ka2 is very less so I am not considering that dissociation.

Now Ka = 8.0*10⁻⁵ = [H3O⁺] [HA⁻] / [H2A]

lets concentration of H3O⁺ = X then above equation will be

8.0*10−5 = [x] [x] / [0.28 -x

8.0*10−5 = x² / [0.28 -x ]

x² + 8.0*10⁻⁵x - 2.24 * 10⁻⁵

solve the quardratic equation

X =0.004693 M

pH = -log[H⁺]

pH = - log [ 0.004693 ]

pH = 2.3285

Hope that helps!

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3 years ago