Question

list the four quantum numbers from LAST electron of each of the following elements in their ground state: sodium, nitrogen, oxygen, chlorine, sulfur

Answer 1

Explanation:

The four quantum  numbers gives the position of the orbital, its spatial orientation, the shape of the orbital and the spin of the an electron in the orbital.

The principal quantum number(n) gives the main energy level in which the orbital is located; n = 1,2,3,4....

Azimuthal or secondary quantum number (l) gives the shape of the orbitals an they take values l = 0,1,2,3.... and their names are s for 0, p for 1, d for 2 and f for 3.

Magnetic quantum number gives the spatial orientation or degeneracy of the orbitals in the subshell.

Spin quantum number gives the spinning of the electrons

Electronic configuration:

Na = 1s² 2s² 2p⁶ 3s¹

   The last electron enters the 3s¹

           n = 3

            l = 0

           m = 0

            spin =+ or - $\frac{1}{2}$

N = 1s² 2s²  2p³

           last electron enters 2p³

              n = 2

              l = 1

               m = -1, 0, 1

               spin = + or - $\frac{1}{2}$

O = 1s² 2s² 2p²

    last electron enters  2p²

             n = 2

              l = 1

               m = -1, 0, 1

               spin = + or - $\frac{1}{2}$

Cl =1s² 2s² 2p⁶ 3s² 3p⁵

     last electron enters 3p⁵

               n = 3

              l = 1

               m = -1, 0, 1

               spin = + or - $\frac{1}{2}$

S = 1s² 2s² 2p⁶ 3s² 3p⁴

      last electron enters 3p⁴

               n = 3

              l = 1

               m = -1, 0, 1

               spin = + or - $\frac{1}{2}$

learn more:

Quantum number brainly.com/question/9288609

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